All categories

3 years ago

Convert 0.0000001 to a power of 10. 107 10−7 106 10−6

2 answers:

4 0

Since you have to move the decimal point the the right by 7 places to get the decimal point after the one. You must multiply by 1/10 seven times, which is the same as:

10^-7

defon3 years ago

4 0

10^-7 = 0.0000001

when the number is a decimal the power is a negative number

You might be interested in

The _____ states that control is enhanced by concentrating on the exceptions to, or significant deviations from, the expected re

dalvyx [7]

The principle of exception is the managerial principle that states that control is enhanced by concentrating on the exceptions to, or significant deviations from, the expected result or standard.
This also refers to the fact that only what is important in a budget or a plan is shown to the manager, while the rest is excluded.

4 0

3 years ago

HELP ASAP what is the value of x enter your answer in the box

Alexxx [7]

Answer:

x=25

Step-by-step explanation:

24²+7²=625

√625= 25

5 0

3 years ago

Read 2 more answers

I FREEking need help on this! You will get some POINTS for it ∵

omeli [17]

What do you need help on? All I see is a y axis and x axis grid.

4 0

3 years ago

Evaluate the surface integral ModifyingBelow Integral from nothing to nothing Integral from nothing to nothing With Upper S f (x

kykrilka [37]

Parameterize $S$ by

$\vec s(u,v)=6\cos u\sin v\,\vec\imath+6\sin u\sin v\,\vec\jmath+6\cos v\,\vec k$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take a normal vector to $S$ ,

$\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}=36\cos u\sin^2v\,\vec\imath+36\sin u\sin^2v\,\vec\jmath+36\cos v\sin v\,\vec k$

which has norm

$\left\|\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}\right\|=36\sin v$

Then the integral of $f(x,y,z)=x^2+y^2$ over $S$ is

$\displaystyle\iint_Sx^2+y^2\,\mathrm dS=\iint_S\left((6\cos u\sin v)^2+(6\sin u\sin v)^2\right)\left\|\frac{\partial\vec s}{\partial v}\times\frac{\partial\vec s}{\partial u}\right\|\,\mathrm du\,\mathrm dv$

$=\displaystyle36^2\int_0^{\pi/2}\int_0^{2\pi}\sin^3v\,\mathrm du\,\mathrm dv=\boxed{1728\pi}$

6 0

4 years ago

In desperate need of help

Anastasy [175]

Answer :2
Explanation:

6 0

2 years ago

Read 2 more answers