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Mandarinka [93]

4 years ago

6

What is the remainder when p(x) is divided by (x-3) please help

1 answer:

bagirrra123 [75]4 years ago

3 0

Answer:

1

Step-by-step explanation:

We will use polynomial remainder theorem or little Bézout's theorem. It states that reminder p(x) divided by (x - a) is p(a). In our case (a = 3) it is p(3) = 1

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Line q passes through (−5, 5) and is parallel to the line 2x + y + 1 = 0.

Fed [463]

Parallel lines has equal slopes.
Equation of the line 2x + y + 1 = 0 in slope intercept form is y = -2x - 1 with slope of -2. Therefore, the slope is -2.

6 0

4 years ago

Read 2 more answers

In △ABC, BM is a median, △BMC is equilateral and MC = 3cm. Through M is drawn line l∥AB that intersects CB at point N. Find:

ruslelena [56]

Answer:

m∠ABC = 60°

The distance from C to AB = 3 cm

The distance from l to AB = 1.5 cm

Step-by-step explanation:

The median of ΔABC = BM

The length of MC = 3 cm

Type of triangle given as ΔBMC = Equilateral triangle

Line MN is parallel to AB and passes through M intersecting CB at N

Given that BM is a median, we have;

MC = AM = 3 cm

BM = MC = CB = 3 cm, from ΔBMC = Equilateral triangle

CN = NB by midpoint theorem

∴ CB = CN + NB = 2·CN = 3 cm

The distance from C to AB = CB = 3 cm

The distance from C to AB = 3 cm

CN = 3/2 = 1.5

CN = NB = 1.5

The distance from l to AB = CN = 1.5 cm

The distance from l to AB = 1.5 cm

m∠ABC = m∠BMC = m∠MBC = 60° Interior angles of an equilateral triangle.

m∠ABC = 60°

6 0

3 years ago

Mei has 8 jars of soup.each jar contains 300 milliliter a of soup.what is the smallest pot mei can use to heat all the sou?

yarga [219]

Answer:

The pot to cook all the soup must be able to hold at least 2.4 liters or 2400 milliliters

8 0

3 years ago

Solve for d.<br><br> 5 = 3d + 2

Flauer [41]

Answer:

1

Step-by-step explanation:

5=3d+2

subtract the 2 on both sides

3=3d

divide 3 on both sides

you get 1

5 0

4 years ago

Read 2 more answers

Lcm of 1,2,12,30,84,165

cricket20 [7]

Answer:

$LCM(1,2,12,30,84,165)=2^2*3*5*7*11*1=4620$

Step-by-step explanation:

To find the LCM of 1,2,12,30,84,165 you must first find the prime factors of 12,30,84 and 165

12| 2 30| 2 84| 2 165| 3

6 | 2 15 | 3 42| 2 55 | 5

3 | 3 5 | 5 21 | 3 11 | 11

1 1 7 | 7 1

1

$12=2^2*3$ $30=2*3*5$ $84=2^2*3*7$ $165=3*5*11$

Now we look for common and uncommon factors with their greatest exponent

LCM(1,2,12,30,84,165)

Common factors with their greatest exponent: $2^2*3*5$

Uncommon factors with their greatest exponent: $7*11*1$

$LCM(1,2,12,30,84,165)=2^2*3*5*7*11*1=4620$

3 0

4 years ago