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NISA [10]
3 years ago
9

If your weight is 132 pounds, how much work is done if you climb a flight of stairs 12 meters high?

Mathematics
1 answer:
Temka [501]3 years ago
6 0

Answer:

7040.76 Joule

Step-by-step explanation:

In order to make yourself be able to climb upstairs, you need to work against the force of gravity. The force with which you pull yourself up is equal to the force of gravity exerted on you by the gravitational force.

So here, the net force involved is Mass(in Kg) multiplied by Acceleration due to gravity.

132 pounds = 59.8742 Kg

Net force = 59.87 × 9.8 = 586.73

As we know, the workdone is calculated by Multiplying the Net force with the Net displacement. Here, in this case the net displacement is 12 meters.

So,

Workdone = 586.73 × 12 = 7040.76 Joule

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Graph y=-6(3)^x<br><br> please do the table and the graph <br><br> 20 POINTS!
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Answer:

<em>Explanation to the answer below... (Answers in the Explanation</em><em>)</em>

Step-by-step explanation:

We Know that our rule is y = y = -6(3)^{x} , which means we can use this rule to find y from x. Since we don't know what X, is, we have to assume numbers like 1, to 7. And there is no space to write on the graph, I'll put a virtual copy of a graph.

1st Point,

y = -6(3)^{x}\\y =  -6(3)^{1}\\y = -6(3)\\y = -18\\x = 1, y = -18

2nd, point

y = -6(3)^x\\ y = -6(3)^2\\y = -6(9)\\y = -54\\x = 2, y = -54

3rd Point

y = -6(3)^x\\y = -6(3)^3\\y = -6(27)\\y = -162\\x = 3, y = -162

4th Point

y = -6(3)^4\\y = -6(81)\\y = -486\\x = 4, y = -486\\

5th Point

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6th Point

y = -6(3)^x\\y = -6(3)^6\\y = -6(729)\\y = -4,374\\x = 6, y = -4,374\\

7th Point (Last Point)

y = -6(3)^x\\y = -6(3)^7\\y = -6(2,187)\\y. = -13,122\\x = 7, y = -13,122

Let's now plot them on the Graph, the values are so big, the graph might look a little odd.

Always remember that we can continue the points infinitely, and there is no stop, The Graph is attached below...

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Answer:

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<u>Since ΔFHG ≅ QRC, the corresponding angles are congruent:</u>

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