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igor_vitrenko [27]
2 years ago
8

What is the best estimate of the perimeter of the figure on the grid if each square has side lengths of 1 mm?

Mathematics
1 answer:
Valentin [98]2 years ago
4 0

Answer:

the ans of this question is 30cm².

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Combine like terms. 5y - 8 - y
Svetlanka [38]
<h3>Question:-</h3>
  • Combine like terms. 5y - 8 - y

<h3>Answer:-</h3>
  • here like terms are 5y,-y
  • solving like terms
  • 5y-y-8(subtracting 5y-y)
  • 4y-8

hence the combination=

\bold {4y - 8}

All the best !

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2 years ago
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Please help me with this question <br><br> image attached
Mumz [18]

Answer:  (D) 9

<u>Step-by-step explanation:</u>

This is an isosceles triangle.  Since the legs are congruent, then the base angles are congruent.

9x + 3 = 84

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Joe bought 16 pounds of flour for $7.<br> How many pounds of flour did he get per dollar?
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112

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The equation of a line is y = 17x -6
julia-pushkina [17]

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(0, -6)

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the point where the line crosses the y-axis has its x value = 0.

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Solve rational inequality x²+x-6/x²-3x-4≤0?​
Fittoniya [83]

Answer:

Step-by-step explanation:

x

2

+

x

−

6

=

(

x

+

3

)

(

x

−

2

)

x

2

−

3

x

−

4

=

(

x

−

4

)

(

x

+

1

)

Each of the linear factors occurs precisely once, so the sign of the given rational expression will change at each of the points where one of the linear factors is zero. That is at:

x

=

−

3

,

−

1

,

2

,

4

Note that when

x

is large, the

x

2

terms will dominate the values of the numerator and denominator, making both positive.

Hence the sign of the value of the rational expression in each of the intervals

(

−

∞

,

−

3

)

,

(

−

3

,

−

1

)

,

(

−

1

,

2

)

,

(

2

,

4

)

and

(

4

,

∞

)

follows the pattern

+

−

+

−

+

. Hence the intervals

(

−

3

,

−

1

)

and

(

2

,

4

)

are both part of the solution set.

When

x

=

−

1

or

x

=

4

, the denominator is zero so the rational expression is undefined. Since the numerator is non-zero at those values, the function will have vertical asymptotes at those points (and not satisfy the inequality).

When

x

=

−

3

or

x

=

2

, the numerator is zero and the denominator is non-zero. So the function will be zero and satisfy the inequality at those points.

Hence the solution is:

x

∈

[

−

3

,

−

1

)

∪

[

2

,

4

)

graph{(x^2+x-6)/(x^2-3x-4) [-10, 10, -5, 5]}

8 0
3 years ago
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