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damaskus [11]
3 years ago
9

Translate the sentence into an equation.

Mathematics
1 answer:
Luba_88 [7]3 years ago
3 0

Answer:

The expression of the given statement is 8 y - 2  = 6.

Step-by-step explanation:

Here, let the unknown number = y

Now, product of y and 8 =  8 times  y   =   8 y

Also, two less than the product    =  Product - 2

So, two less than the product  of 8 and y =  8 y - 2

Now, this above expression is equivalent to 6.

⇒8 y - 2  = 6

Hence the expression of the given statement is 8 y - 2  = 6.

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Irina-Kira [14]

Hope you understand the solution. Call my attention if you need any help

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2 years ago
2/35=x/140 solve the proportion
tamaranim1 [39]

\frac{2}{35}=\frac{x}{140}    Multiply 140 on both sides to get "x" by itself

(140)\frac{2}{35}=\frac{x}{140} (140)

\frac{280}{35}=x

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3 years ago
The ratio of a number and 4 times that number is equal to the ratio of 5 times the number and 95 more than a number
il63 [147K]

Answer:

  1/4 = (5n)/(n +95)

Step-by-step explanation:

If all the numbers referred to are the same number, we can use n to represent it. Then, "the ratio of a number and 4 times that number" is n/(4n) = 1/4. "The ratio of 5 times the number and 95 more than the number" is (5n)/(n+95)

The equation for the problem can be written ...

  1/4 = (5n)/(95+n)

___

If you're a purist, you might leave the factors of "a number" in the first raio and write it ...

  n/(4n) = (5n)/(95+n)

Solving this gets you to a quadratic form that has the extraneous solution n=0.

8 0
3 years ago
Surface Area of a Rectangle please help
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Answer:

Step-by-step explanation:

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3 years ago
The half life of a certain tranquilizer in the bloodstream is 36 hours. How long will it take for the drug to decay to 87% of th
Fudgin [204]

<u>Finding the Decay constant(λ):</u>

λ = 0.693 / (half-life)

we are given that the half-life is 36 hours

λ = 0.693 / (36)

λ = 0.01925 /hour

<u>Time taken for 87% decay:</u>

Since decay is first-order, we will use the formula:

t = \frac{2.303}{decay constant}log(\frac{A_0}{A} )

Where A₀ is the initial amount and A is the final amount

Let the initial amount be 100 mg,

the final amount will be 87% of 100

Final amount = 100*87/100 = 87 mg

<em>Replacing the values in the equation: </em>

<em />t = \frac{2.303}{0.01925}log(\frac{100}{87} )<em />

<em />t = \frac{2.303}{0.01925}*0.06<em />

t = 7.18 hours

<em>We used 'hours' as the unit because the unit of the decay constant is '/hour'</em>

Therefore, the drug will decay to 87% of initial dosage after 7.18 hours

7 0
3 years ago
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