Answer:
Option B. ![\frac{1}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D)
Step-by-step explanation:
we know that
The frequency is equal to the number of cycles divided by the time
Remember that
1 cycle = 1 full wave to repeat itself
In this problem
From o to 12 seconds ------> there are 2 cycles
therefore
The frequency is equal to
![f=\frac{2}{12}=\frac{1}{6}](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B2%7D%7B12%7D%3D%5Cfrac%7B1%7D%7B6%7D)
Answer: 72
Step-by-step explanation:
25:18 - 25 total : 18 made
25:18 x 4 = 100:72
100:72- 100 total : 72 made
First, find the mean. You'll need it to compute the variance.
![\bar x=\displaystyle\frac15\sum_{i=1}^5x_i=\dfrac{21+10+6+7+11}5=11](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cdisplaystyle%5Cfrac15%5Csum_%7Bi%3D1%7D%5E5x_i%3D%5Cdfrac%7B21%2B10%2B6%2B7%2B11%7D5%3D11)
The variance of the sample is then computed with the formula
![s^2=\displaystyle\dfrac1{5-1}\sum_{i=1}^5(\bar x-x_i)^2=\dfrac{(21-11)^2+\cdots+(11-11)^2}4=\dfrac{71}2=35.5](https://tex.z-dn.net/?f=s%5E2%3D%5Cdisplaystyle%5Cdfrac1%7B5-1%7D%5Csum_%7Bi%3D1%7D%5E5%28%5Cbar%20x-x_i%29%5E2%3D%5Cdfrac%7B%2821-11%29%5E2%2B%5Ccdots%2B%2811-11%29%5E2%7D4%3D%5Cdfrac%7B71%7D2%3D35.5)
The standard deviation is the square root of the variance, so
Answer:
17.07m/s
Step-by-step explanation:
v=d/t
d=956km
t=56sec
v=956/56
v=17.07m/s
Answers:
- Discrete
- Continuous
- Discrete
- Continuous
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Explanations:
- This is discrete because we can't have half a basketball, or any non-whole decimal value to represent the number of basketballs. We can only consider positive whole numbers {1,2,3,4,...}. A discrete set like this has gaps between items. In other words, the midpoint of 2 and 3 (the value 2.5) isn't a valid number of basketballs.
- This is continuous because time values are continuous. We can take any two different markers in time, and find a midpoint between them. For example, the midpoint of 5 minutes and 17 minutes is 11 minutes since (5+17)/2 = 22/2 = 11. Continuous sets like this do not have any gaps between items. We can consider this to be densely packed.
- This is the same as problem 1, so we have another discrete function. You either score a bullseye or you don't. We can't score half a bullseye. The only possible values are {1,2,3,4,...}
- This is similar to problem 2. This function is continuous. Pick any two different positive real numbers to represent the amount of gallons of water. You will always be able to find a midpoint between those values (eg: we can have half a gallon) and such a measurement makes sense.
So in short, always try to ask the question: Can I pick two different values, compute the midpoint, and have that midpoint make sense? If so, then you're dealing with a continuous variable. Otherwise, the data is discrete.