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PSYCHO15rus [73]
3 years ago
7

What is the answer? r=4 b=6 d=5

Mathematics
1 answer:
bazaltina [42]3 years ago
6 0

Answer:

32

Step-by-step explanation:

sqrt r = 2

b*d = 30

30+2 = 32

Hopefully that helps

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The number of patients treated at Dr. McCormick’s dentist office each day was recorded for nine days. These are the data: 13, 16
NARA [144]
First, lets sort the list from smallest to greatest. This will help with median, mode, and range.

4, 6, 10, 12, 12, 13, 16, 16, 16

Next, lets find the mean. Mean is found by adding all numbers up, then dividing them by the number of entries in the data set.

4+6+10+12+12+13+16+16+16 = 105
105 / 9 = 11.7

So the mean is 11.7.

Next, we'll find the median. The median is the value in the center of the list. Because there are 9 values, that means the center of the list is 5 with four numbers on each side of it. The 5th number in the list is 12, so that's our median.

Continuing, the mode is the number or numbers that appears the most often. For this data set, 16 appears 3 times while all other numbers appear 2 times or less. So, the mode is 16.

Lastly, the range is the difference between the largest number and the smallest number.

16 - 4 = 12

So the range is 12.

The second answer in the list matches all of these values, and is the correct solution.
7 0
2 years ago
Read 2 more answers
What property justifies this statement
Varvara68 [4.7K]

Answer:

B. SUBTRACTION PROPERTY OF EQUALITY

Step-by-step explanation:


4 0
3 years ago
Shelby spends 2/7 of her salary on her monthly rent and has $3455 left over. How much does she spend on her rent each month?
Zepler [3.9K]

Answer:

$1382

3455 is 5/7 of salary so divide 3455/5 = 691

then multiply 691x2 because rent is 2/7 of salary

691x2 = 1382

5 0
2 years ago
he data represents the daily rainfall​ (in inches) for one month. Construct a frequency distribution beginning with a lower clas
Licemer1 [7]

Answer:

It is not normally distributed as it has it main concentration in only one side.

Step-by-step explanation:

So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).

So, let us begin the groupings into their different classes, shall we?

Data given:

0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.

(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.

(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31

(3). 0.4 - 0.6 : there are 2 values that falls into this category.

(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.

Class interval            frequency.

0.00 - 0.20.                   15.

0.20 - 0.40.                    2.

0.4 - 0.6.                        2.

4 0
3 years ago
Please help using the picture below I need the surface area I also need an explanation
Taya2010 [7]

Answer:

155

Step-by-step explanation:

5*5=25

((5*13)/2)*4=130

130+25=155

6 0
2 years ago
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