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3 years ago

If M <1 = 115 degrees what is m <2

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

6 0

Answer:

M<2= 65

Step-by-step explanation:

The reason it is 65 because 2 angles add up to either 90 or 180 and in this case it would be 180.

You would use angle addition postulate to find the answer so M<1 + M<2 = 180.

Since M<1 is 115 you would substitute it into the formula so 115 + M<2 = 180

Then you would subtract 115 from 180 in which you would get M<2 = 65

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8 1/4 divied by d = 2/11 what is d

Luda [366]

Answer:

d = 363/8

Step-by-step explanation:

Let's write this as a fraction:

8 1/4 2

------------- = -------

d 11

One way in which this could be approached would be to interchange 'd' and '2:'

8 1/4 d 33 d

------------- = ------- or -------- = ---------

2 11 4(2) 11

Multiplying both sides by 11 isolates d:

33(11) 363

-------- = d, or d = ----------

8 8

7 0

2 years ago

Determine the horizontal vertical and slant asymptote y=x^2+2x-3/x-7

lilavasa [31]

Answer:

<h2>A.Vertical:x=7</h2><h2>Slant:y=x+9</h2>

Step-by-step explanation:

$f(x)=\dfrac{x^2+2x-3}{x-7}\\\\vertical\ asymptote:\\\\x-7=0\qquad\text{add 7 to both sides}\\\\\boxed{x=7}\\\\horizontal\ asymptote:\\\\\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{x\left(1-\frac{7}{x}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{x\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{1-\frac{7}{x}}=\pm\infty\\\\\boxed{not\ exist}$

$slant\ asymptote:\\\\y=ax+b\\\\a=\lim\limits_{x\to\pm\infty}\dfrac{f(x)}{x}\\\\b=\lim\limits_{x\to\pm\infty}(f(x)-ax)\\\\a=\lim\limits_{x\to\pm\infty}\dfrac{\frac{x^2+2x-3}{x-7}}{x}=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x(x-7)}=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x^2-7x}\\\\=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{x^2\left(1-\frac{7}{x}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{1+\frac{2}{x}-\frac{3}{x^2}}{1-\frac{7}{x}}=\dfrac{1}{1}=1$

$b=\lim\limits_{x\to\pm\infty}\left(\dfrac{x^2+2x-3}{x-7}-1x\right)=\lim\limits_{x\to\pm\infty}\left(\dfrac{x^2+2x-3}{x-7}-\dfrac{x(x-7)}{x-7}\right)\\\\=\lim\limits_{x\to\pm\infty}\left(\dfrac{x^2+2x-3}{x-7}-\dfrac{x^2-7x}{x-7}\right)=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3-(x^2-7x)}{x-7}\\\\=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3-x^2+7x}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{9x-3}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{x\left(9-\frac{3}{x}\right)}{x\left(1-\frac{7}{x}\right)}$

$=\lim\limits_{x\to\pm\infty}\dfrac{9-\frac{3}{x}}{1-\frac{7}{x}}=\dfrac{9}{1}=9\\\\\boxed{y=1x+9}$

8 0

3 years ago

Malik borrowed $1,800 from the bank at a rate of 8% simple interest per year.Over the course of three years ,how much interest d

sergij07 [2.7K]

I’m gonna say c? Good luck!

5 0

3 years ago

Read 2 more answers

If 3x - 2y = 9 , 27x³- 8y³= 1377 , prove that xy = 4 <br><br><br><br>plzz answer this question...

solniwko [45]

Step-by-step explanation:

Here we are given that , the Value of

$3x - 2y = 9$
$27x^3 - 8y^3 = 1377$

And we need to find the prove that ,

$xy = 4$

We know a identity as ,

$(a-b)^3 = a^3-b^3-3ab(a-b)$

On cubing both sides of the given equation,

$(3x-2y)^3 = 9^3$

Simplify and then substitute ,

$27x^3-8y^3 -3(3x)(2y)(3x-2y ) = 729$

$1377 - 18xy (9) = 729$

$162xy = 1377-729$

$xy =\dfrac{648}{162}$

$xy = 4$

Hence Proved !

8 0

3 years ago

A copy machine makes 24 copies per minute. how many copies does it make in 5 minutes and 30 seconds

enot [183]

In 1 minute the copy machine copies = 24
That means
In 60 seconds the copy machine copies = 24
First we need to convert 5 minutes and 30 seconds to seconds
Then
5 minutes and 30 seconds = (5 * 60) + 30
   = 300 + 30
   = 330 seconds
So
In 330 seconds the copy machine will copy = (24/60) * 330
   = 4 * 33
   = 132
So in 5 minutes and 30 seconds the copy machine will copy 132 copies.

6 0

3 years ago

Read 2 more answers