keeping in mind that when the logarithm base is omitted, the base 10 is assumed.
![\textit{exponential form of a logarithm} \\\\ \log_a(b)=y \qquad \implies \qquad a^y= b \\\\[-0.35em] ~\dotfill\\\\ \log(x)=2\implies \log_{10}(x)=2\implies 10^2=x\implies 100=x](https://tex.z-dn.net/?f=%5Ctextit%7Bexponential%20form%20of%20a%20logarithm%7D%20%5C%5C%5C%5C%20%5Clog_a%28b%29%3Dy%20%5Cqquad%20%5Cimplies%20%5Cqquad%20a%5Ey%3D%20b%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Clog%28x%29%3D2%5Cimplies%20%5Clog_%7B10%7D%28x%29%3D2%5Cimplies%2010%5E2%3Dx%5Cimplies%20100%3Dx)
I’m assuming the answer is HL since they only gave us two letters.
Answer:
Scatter plot
Step-by-step explanation:
Answer is 5
Answer:
The value of Mary's investment after two years = £12362.7
Step-by-step explanation:P = Principal / initial amountR = rate of interest per cent per yearT = number of yearsA = final amount at the end of T yearsThen:A = P*(1 + R/100)^2In our example:P = £12000R = 1.5 per cent per yearT = 2 yearsThus:A = 12000*(1 + 1.5/100)^2 = 12000*(1 + 0.015)^2 = 12000*(1.015)^2 = 12000*(1.030225) = 12362.7Value of investment after two years = £12362.7
