What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Answer:
x ≈ 4.6
Step-by-step explanation:
Reference angle = 75°
Opposite side to reference angle = 17
Adjacent side = x
Applying TOA:
Tan 75 = opp/adj
Tan 75 = 17/x
Multiply both sides by x
x*Tan 75 = 17
Divide both sides by Tan 75
x = 17/Tan 75
x ≈ 4.6
Answer:
12 over 5, or 2.4
Step-by-step explanation:
I plugged it in my graphic calculator.
you can buy about 4 tapes
Hope my answer helped
Answer:
-12
Step-by-step explanation:
