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2 years ago

The gandhara region is the home of many portrayals of ____.

1 answer:

3 0

BUDDHA. It is a cold climate region where many BUDDHA carvings, with simplistic garments and appearance can be seen. This also exemplifies Gandhara art work that is usually influenced by roman empire.

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Helpppppplpppo! Hurry hurry

vfiekz [6]

Answer:

I hurried wat

Step-by-step explanation:

wAT

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2 years ago

What is the answer to the question " 6(5x(41-36)-(8+14))

alisha [4.7K]

So 41-36=5, 5x5=25, which makes it 6(25-(8+14)). So then it's 6(25-22), which is 6x3, which is 18. (So 18 is the answer).

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3 years ago

Solve For d.<br> d+ 4 = 16.21<br> d=12.21

pshichka [43]

This comes from subtracting 4 from both sides.

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1 year ago

A piecewise function g(x) is defined by g(x)={x^3-4x for x<2, -log_4(x-1)+2 for x>=2

storchak [24]

The x-intercepts of the piecewise function are 1.59 and 17 and the intervals where g(x) is positive are (-2,0) and [2,17)

<h3>The graph of the function</h3>

The piecewise function is given as:

$g(x) = \left[\begin{array}{cc}x^3-4x &x < 2\\-\log_4(x - 1) + 2 &x \ge 2\end{array}\right$

See attachment for the graph of the piecewise function.

<h3>The x-intercepts of the piecewise function</h3>

This is the point where the piecewise function crosses the x-axis.

From the attached graph, the graph crosses the x-axis at x = -2, x = 0 and x = 17

Hence, the x-intercepts of the piecewise function are -2, 0 and 17

<h3>The intervals where g(x) is positive</h3>

This is the range of x value where g(x) > 0

From the attached graph, g(x)> 0 between x = -2 & x = 0 and between x = 2 (inclusive) & x = 17

Hence, the intervals where g(x) is positive are (-2,0) and [2,17)

Read more about piecewise function at:

brainly.com/question/11827078

#SPJ1

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1 year ago

Find a potential function for F or determine that F is not conservative. (If F is not conservative, enter NOT CONSERVATIVE.) F =

xxMikexx [17]

For $F$ to be conservative, we need to have

$\dfrac{\partial f}{\partial x}=\cos z$

$\dfrac{\partial f}{\partial y}=10y$

$\dfrac{\partial f}{\partial z}=-x\sin z$

Integrate the first PDE with respect to $x$ :

$\displaystyle\int\frac{\partial f}{\partial x}\,\mathrm dx+\int\cos z\,\mathrm dx\implies f(x,y,z)=x\cos z+g(y,z)$

Differentiate with respect to $y$ :

$\dfrac{\partial f}{\partial y}=10y=\dfrac{\partial g}{\partial y}\implies g(y,z)=5y^2+h(z)$

Now differentiate $f$ with respect to $z$ :

$\dfrac{\partial f}{\partial z}=-x\sin z=-x\sin z+\dfrac{\mathrm dh}{\mathrm dz}\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C$

So we have

$f(x,y,z)=x\cos z+5y^2+C$

so $F$ is indeed conservative.

8 0

3 years ago