Gathering information with your eyes is called

Write a program that uses the function isPalindrome given in Example 6-6 (Palindrome). Test your program on the following string

WITCHER [35]

Answer:

Explanation:

bool isPalindrome(string str)

{

int length = str.length();

for (int i = 0; i < length / 2; i++) {

if (str [i] != str [length – 1 – i]) {

return false;

}

cout << str << "is a palindrome";

return true;

}

3 0

3 years ago

which of the following is not a driver of wireless growth? group of answer choices universal access to information and applicati

AysviL [449]

The invention of the micro hard drive is not a driver of wireless growth.

What is Hard Drive (HDD)?

A computer hard drive (also known as a hard disk or HDD) is a type of technology that stores your computer's operating system, applications, and data files such as documents, pictures, and music. The rest of your computer's components work together to display the applications and files stored on ones hard drive.

How does a Hard Drive (HDD) work?

A hard disk drive (HDD) is made up of a platter with data storage compartments. This information includes your operating system, applications, and any files that you have created. There's also an accuator arm that keeps moving across the platter to read or write the data. The platter spins as the accuator arm movements across it to speed up the process.

To learn more about Hard Drive (HDD), visit: brainly.com/question/27269845

#SPJ4

6 0

1 year ago

What led to fall of axum?

stiks02 [169]

The main factors that led to the fall of the Aksum in the seventh century were climate change and the obstruction of international trade routes around the Red Sea brought on by the growing supremacy of the Muslims in Ethiopia. Other contributing factors included a reduced crop yield due to excess cultivation of land, Persian interference and the rise of Christianity in the region.

3 0

3 years ago

Read 2 more answers

a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv

Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

#include <bits/stdc++.h>

using namespace std;

// chracter to digit mapping, and the inverse

// (if you want better performance: use array instead of unordered_map)

unordered_map<char, int> c2i;

unordered_map<int, char> i2c;

int ans = 0;

// limit: length of result

int limit = 0;

// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]

bool helper(vector<string>& words, string& result, int digit, int widx, int sum) {

if (digit == limit) {

ans += (sum == 0);

return sum == 0;

}

// if summation at digit position complete, validate it with result[digit].

if (widx == words.size()) {

if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {

if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result

return false;

c2i[result[digit]] = sum % 10;

i2c[sum%10] = result[digit];

bool tmp = helper(words, result, digit+1, 0, sum/10);

c2i.erase(result[digit]);

i2c.erase(sum%10);

ans += tmp;

return tmp;

} else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){

if (digit + 1 == limit && 0 == c2i[result[digit]]) {

return false;

}

return helper(words, result, digit+1, 0, sum/10);

} else {

return false;

}

// if word[widx] length less than digit, ignore and go to next word

if (digit >= words[widx].length()) {

return helper(words, result, digit, widx+1, sum);

}

// if word[widx][digit] already mapped to a value

if (c2i.count(words[widx][digit])) {

if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0)

return false;

return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);

}

// if word[widx][digit] not mapped to a value yet

for (int i = 0; i < 10; i++) {

if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;

if (i2c.count(i)) continue;

c2i[words[widx][digit]] = i;

i2c[i] = words[widx][digit];

bool tmp = helper(words, result, digit, widx+1, sum+i);

c2i.erase(words[widx][digit]);

i2c.erase(i);

}

return false;

}

void isSolvable(vector<string>& words, string result) {

limit = result.length();

for (auto &w: words)

if (w.length() > limit)

return;

for (auto&w:words)

reverse(w.begin(), w.end());

reverse(result.begin(), result.end());

int aa = helper(words, result, 0, 0, 0);

}

int main()

{

ans = 0;

vector<string> words={"GREEN" , "BLUE"} ;

string result = "BLACK";

isSolvable(words, result);

cout << ans << "\n";

return 0;

}

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0

2 years ago

Elements such as page parts and calendars are easily inserted by navigating to the _____ grouping. Building Blocks Illustrations

yaroslaw [1]

Answer:

Building Blocks

Explanation:

When referring to the Publisher Application the navigation feature that allows you to do this is the Building Blocks feature. Like mentioned in the question this feature allows you to choose from and insert a predefined set of calendars for insertion into a publication as well as insert a variety of other page parts to better customize the feel of the publication.

6 0

3 years ago