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Alecsey [184]
3 years ago
15

Jeff wants to print quickly so he presses the Ctrl and the P. Jeff used a _____. macro invoice template shortcut

Computers and Technology
1 answer:
Allushta [10]3 years ago
3 0
He used a keyboard shortcut.
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Your organization recently deployed a Windows domain controller with Active Directory. All the domain OU users need to run the s
liberstina [14]

<u>Normally windows end user can login 3 ways as follow:</u>

1. End user can Login as local account where user has not connected or even connected to local Area network LAN.

2. Next user can login into cloud accounts nothing but hot mail  accounts

3. Login to windows domain controller where end user should connect to LAN.

Purpose of installation of Windows domain controller with Active Directory is to keep trace and keep log history activities.

Due to windows domain controller with Active Directory end user desktop or laptop has control on software access also.

Every time when end user login on windows domain controller a small modified is executed whenever is required. It is not going effort the workstation performances.

Note: - Domain severs should be POWER on first.

5 0
3 years ago
Given: an int variable k, an int array current Members that has been declared and initialized, an int variable memberID that has
Alekssandra [29.7K]

Answer:

The c++ program is given below. Nothing is displayed as per the question.

#include <iostream>

using namespace std;

int main() {    

   // declaration and initialization of integer variables

   int k, memberID = 12, nMembers=5;

   bool isAMember;    

   // declaration and initialization of integer array

   int currentMembers[] = {12, 34, 56, 78, 90};    

   for(k=0; k<nMembers; k++)

   {

       if(memberID == currentMembers[k])

       {

           // when member is found in the array, the loop is exited using break

           isAMember = true;

           break;

       }

       else

           isAMember = false;

   }    

   return 0;

}

Explanation:

The program begins with declaration and initialization of integer variables and followed by initialization of the array holding the id of all the members.

The Boolean variable is declared but not initialized.

int k, memberID = 12, nMembers=5;

bool isAMember;

int currentMembers[] = {12, 34, 56, 78, 90};

After this, the array holding the id of the members is searched for the given member id. This is done using  a for loop and a if else statement inside the loop.

If the member id is present in the array, the variable isAMember is initialized to true otherwise it is assigned false.

When the variable isAMember is initialized to true, the break statement is used to exit from the loop.

for(k=0; k<nMembers; k++)

   {

       if(memberID == currentMembers[k])

       {

           isAMember = true;

           break;

       }

       else

           isAMember = false;

 }

The break is used since other values of id in the array will not match the given member id and the variable, isAMember will be initialized to false even if the given member id is present in the array. Hence, it is mandatory to exit the loop once the given member id is found in the array.

This program can be tested for different values of the id of the members and different sizes of the array.

4 0
4 years ago
What are the three major functions of a game engine?
Harrizon [31]
read that hope this helped

8 0
3 years ago
Which tab is used to insert a hyperlink onto a slide
Roman55 [17]
The tab used to instead a Hyperlink into a slide is the Insert tab under the “Links” group.
5 0
3 years ago
Read 2 more answers
Write the program to solve quadratic equations, but if the discriminant is negative, output
Firdavs [7]

Answer:

PROGRAM  QuadraticEquation Solver

  IMPLICIT  NONE

REAL :: a, b, c ;

  REA :: d ;

  REAL  :: root1, root2 ;

//read in the coefficients a, b and c

  READ(*,*)    a, b, c  

  WRITE(*,*)   'a = ', a

  WRITE(*,*)   'b = ', b

  WRITE(*,*)    'c = ', c

  WRITE(*,*)

// computing the square root of discriminant d

  d = b*b - 4.0*a*c

  IF (d >= 0.0) THEN              //checking if it is solvable?

     d     = SQRT(d)

     root1 = (-b + d)/(2.0*a)     // first root

     root2 = (-b - d)/(2.0*a)     // second root

     WRITE(*,*)  'Roots are ', root1, ' and ', root2

  ELSE                            //complex roots

     WRITE(*,*)  'There is no real roots!'

     WRITE(*,*)  'Discriminant = ', d

  END IF

END PROGRAM  QuadraticEquationSolver

8 0
4 years ago
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