Well what’s the entire problem
Answer:
Ans.1.) X = 7.
Ans.2.a.) AC =JL.
Ans.2.b.) BC = KL.
Step-by-step explanation:
For Question 1.
As we know vertically opposite angles are equal.

For Question 2.a)

For Question 2.b)

Answer:
12
Step-by-step explanation:
V=πr2h=π·22·3≈37.69911
<span>In two similar triangles, like the one we see above, the ratio of their areas is the square of the ratio of their sides.
Based on the graph, we see that BD is 3 times larger than BA. This means that the area of DBE will be 3</span>² times larger, or 9 times larger, than the area of ABC.
Area of ABC = 3 square units
Area of DBE = 3 * 9 = 27 square units
Answer is A.
You would probably have to repeat the 7th grade, because you need to have a certain GPA, and 2 F's mean that you are only able to get 2.0 GPA, maximum. Otherwise, you'll fail. So, you have a very small chance of passing.