Find the median, first quartile, third quartile, and interquartile range of the data
1 answer:
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Answer:
this mean amount of coffee to be dispensed would be 11.99, approximately 12
Step-by-step explanation:
first of all we have this information available to answer this question.
standard deviation σ = 0.006 ounces
prob(x > 12) = 0.04
we use this formular to find the mean
z = x - μ/σ
the value of the z score at 4% is equal to 1.7507
such that
we cross multiply from this stage
1.7507*0.006 = 12-μ
0.0105042 = 12-μ
μ = 12 - 0.0105042
herefore, the mean amount μ = 11.99 this can be approximated to 12
The demand that has an 8% probability of being exceeded is 38.1230 .
<h3>What is probability?</h3>Probability is the aspect of mathematics that focus on the occurrence of a random event.
This is calculated below:
The normal random variable having the mean is been given as :
(Mu = 31.8)
The standard deviation is been given as ( sd = 4.5)
Then in making our calculation, we will need to make use of the formular below:
But we know that going with the probability of 0.08
where k = 1.4051
P (Z > 1.4051)
k = 1.4051
we can have the expression for k as
This can be simplified as:
X = 4.5 (1.4051) + 31.8 = 38.1230.
Therefore, the demand that has an 8% probability of being exceeded is 38.1230 .
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