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2 years ago

Find the median, first quartile, third quartile, and interquartile range of the data

Mathematics

1 answer:

s344n2d4d5 [400]2 years ago

6 0

Answer:

median 88 first 84 third 92

Step-by-step explanation:

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Simplify -4.5 + (-1.5)

mojhsa [17]

-4.5 + (-1.5)

-4.5 + 1.5

-6

5 0

2 years ago

Read 2 more answers

Y=x???need answers and an explanation

Lesechka [4]

Y= 2
every time y goes up it goes up by 2

-1+2=1
1+2=3
3+2=5

5 0

3 years ago

Solve x/-4 > 8 1. x > -2 2. x < -32 3. x < -2 4. x > -32

Gnom [1K]

Answer:

x<-32

Step-by-step explanation:

I hope this helped have a good night

8 0

3 years ago

If a= .75 and b= .50, what is the perimeter of the rectangle?

Lerok [7]

Answer:

C. 14 inches

Step-by-step explanation:

The perimeter is double the sum of length and width:

P = 2((4a +3) +(6b -2) = 8a +12b +2

For the given values, this is ...

P = 8(0.75) +12(0.50) +2 = 6 + 6 + 2 = 14

The perimeter is 14 inches.

3 0

3 years ago

Find cot theta. (-6,-3sqrt(5)

cupoosta [38]

0 Pretend that is theta XD

cot 0 = $\frac{1}{tan0}$

Find tan 0.

tan 0 = $\frac{y}{x}$

tan 0 = $\frac{-3\sqrt{5}}{-6}$

tan 0 = $\frac{\sqrt{5}}{2}$

cot 0 = $\frac{1}{tan0}$

cot 0 = $\frac{1}{\frac{\sqrt{5} }{2} }$

Multiply 2/√5 to the numerator and the denominator (or multiply the reciprocal of the denominator to the top and bottom of the fraction)

cot 0 = $\frac{1}{\frac{\sqrt{5}}{2} } (\frac{\frac{2}{\sqrt{5}} }{\frac{2}{\sqrt{5}}} )$

cot 0 = $\frac{2}{\sqrt{5}}$

Multiply √5 to the numerator and the denominator

cot 0 = $\frac{2}{\sqrt{5}} (\frac{\sqrt{5} }{\sqrt{5} })$

cot 0 = $\frac{2\sqrt{5}}{5}$

5 0

3 years ago