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Alexandra [31]
2 years ago
7

Find the median, first quartile, third quartile, and interquartile range of the data

Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
6 0

Answer:

median 88 first 84 third 92

Step-by-step explanation:

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What are considered measures of variability
shusha [124]
Statisticians use summary measures to describe the amount of variability or spread in a set of data. The most common measures of variability are the range, theinterquartile<span> range (</span>IQR<span>), </span>variance<span>, and standard deviation. This is from google btw</span>
7 0
3 years ago
Ussions
ankoles [38]

Answer:

All points on line CD are equidistant from A and B

Step-by-step explanation:

Given that point A is the center of circle A and point B is the center of circle B,  and the circumference of circle A passes through the center of circle B which is point B and vice versa.

Therefore we have;

The radius of circle A = The radius of circle B

Which gives;

The distance of the point C to the center A is equal to the distance of the point C to the center B

Similarly, the distance of the point D to the center A is equal to the distance of the point D to the center B

So also the distances of all points on the line from the center A  is equal to the distances of all points on the line from the center B.

6 0
2 years ago
Please help I will mark brainlist if correct
Setler79 [48]
Y = 3x + 13

You can get this by using the same slope and then plugging into the equation to find the intercept. <span />
8 0
3 years ago
How would you calculate 7x + 1=68 with only one variable? (Working please)
Tanya [424]
Well if you're solving for x this would be rather simple. 7x +1=68   , then you'd minus 1 from both sides. 7x = 67   then divide 67 by 7. The answer isn't a whole number so x would either be 67/7 or 9.57.. etc. 
6 0
3 years ago
I need to find all real values of x from this inequality x^2&gt;2x-2 and also this question x^2&gt;2x+2. I need the answer fast
sergeinik [125]

x^2\gt2x-2

x^2-2x+2\gt0

You are essentially asking at this point where is the quadratic function greater than 0. To get the interval find the roots. Between the roots the function is guaranteed to be LESS THAN zero. Everywhere else the function is greater than 0.

x^2-2x+2=0

Use Vieta's rule to get the roots,

(x-1)(x-1)=0

Both roots are the same so no value is less than 0 which means all values except at the point of root are strictly greater, the point of root is at x_{1,2}=1 which means the set for which the quadratic function is greater than 0 is \mathbb{R}-\{1\} "all real numbers except 1".

To convert this into interval notation use all numbers up to 1 but not including and all numbers after 1 but not including,

(-\infty,1)\cup(1,\infty)

Hope this helps :)

7 0
3 years ago
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