Solve this quadratic equation by completing the square. (2x^2 = -8x + 45)

1 answer:

8 0

$(2x^2 = -8x + 45) \\ \\ 2x^2 + 8x - 45 = 0 \\ \\ x = \frac{-8+2 \sqrt{106} }{4} , \frac{-8-2 \sqrt{106} }{4} \\ \\ x = - \frac{4- \sqrt{106} }{2} , - \frac{4+ \sqrt{106} }{2} \\ \\ Answer: x = - \frac{4- \sqrt{106} }{2} , - \frac{4+ \sqrt{106} }{2}$

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See the step-by-step solution in the picture attached below.

I hope this answer will help you. Have a nice day !