<span>A group of men and women were asked what their favorite pet was, and the results of the survey were tabulated. Let event B be defined as randomly choosing someone who picked cats or dogs as their favorite pet.
</span>(d) 3/4
1) x+y = 170
x-y = 26
2) Subtract the two equations from each other. Doing this you get 2y = 56.
So the value of y is 28. Then plug in the value of y into any of the two equations and solve for x.
x-28 = 26
x = 54
3) When writing solutions as an ordered pair, the x value always comes first followed by the y value. So it would be (54, 28).
Answer:
They can paint 18. 66 sq ft with 3 gallons of paint.
Step-by-step explanation:
Total area painted = 280 sq ft
Total gallons of paint used = 45
So, 45 gallons of paint painted 280 sq ft.
⇒ By UNITARY METHOD,
1 gallon of paint paints 
sq ft
So, area painted by 1 gallon = 6.22 sq ft
⇒ area painted by 3 gallon = 6.22 sq ft x 3 = 18. 66 sq ft
So, they can paint 18. 66 sq ft with 3 gallons of paint.
Step-by-step explanation:
For y/x to be as high as possible, y must have the highest possible value and x must have the lowest possible value. (12 and 6)
Hence, y/x < 12/6, which is 2.
For y/x to be as low as possible, y must have the lowest possible value and x must have the highest possible value (10 and 7)
Hence, y/x > 10/7.
Combining the 2 inequalities, we have 10/7 < y/x < 2.
