Answer:
1) one
2) zero
Step-by-step explanation:
e/sinE = g/sinG
10/sin64 = 9/sinG
sinG = 0.8089146417
G = 53.99
j/sinJ = k/sinK
3/sin129 = 8/sinK
sinK = 2.072389241
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
<h3>What is the least number of buses needed to carry 710 passengers? </h3>
Given that;
- Number of passengers n = 710
- Least number of buses need B = ?
To get the least number of buses, we say;
Number of buses B = 710 ÷ 150
Number of buses B = 4.7 ≈ 5
The least number of buses needed to carry 710 passengers is 5.
Option A)5 is the correct answer.
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Answer:
please can u give full question
Okay. You have 15 lbs of concrete, and x bags that can individually hold 2.5 lbs. What you need to do is divide 15 by 2.5, and the quotient will be 6.
Problem: 15 ÷ 2.5 = 6
So the answer to your problem will be: 6 bags.
Your answer will be -2·y-10<16