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frutty [35]
3 years ago
10

Explain how equal groups, multiplication, addition, and arrays related?

Mathematics
2 answers:
natulia [17]3 years ago
4 0

Answer:

An arrangement of objects, pictures, or numbers in columns and rows is called an array. Arrays are useful representations of multiplication concepts. This array has 4 rows and 3 columns. It can also be described as a 4 by 3 array.

Step-by-step explanation:

hope this helps i looked it up if not im srry

Alex Ar [27]3 years ago
4 0

Answer:

They are similar in many ways.

Step-by-step explanation:

Arrays are useful representations of multiplication concepts. Multiplication is similar to arrays because arrays use columns and rows to represent the digits and numbers in the equation. Addition is similar to the two because you can repeat it and you will get the same product (or sum). Equal groups are similar because it has the same number of items inside. It can be similar to all the others. So that is why they are related.

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Find the area between y = 8 sin ( x ) y=8sin⁡(x) and y = 8 cos ( x ) y=8cos⁡(x) over the interval [ 0 , π ] . [0,π]. (Use decima
Marina86 [1]

Answer:

0.416 au

Step-by-step explanation:

Let y1=8sin(x) and y2=8cos(x), we must find the area between y1 and y2

\int\limits^\pi _0{(8cos(x)-8sin(x))} \, dx = 8\int\limits^\pi _0{(cos(x)-sin(x))} \, dx =\\8(sin(x)+cos(x)) evaluated(0-\pi )=\\8(sin(\pi )-sin(0))+8(cos(\pi )-cos(0))=\\8(0.054-0)+8(0.998-1)=8(0.054)+8(-0.002)=0.432-0.016=0.416

3 0
3 years ago
The Hamilton Brush Company issued 2,500 shares of common stock worth $100,000.00 total. What is the par value of each share?
alexandr1967 [171]
What we know here is that all 2500 shares together are worth 100 000 dollars in total. (it's 100 000.00 actually, but we can ignore the part after the point, as it's equal to 0).

This means that each of the shares is valid the whole sum divided by the number of shares, that is:
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4 0
3 years ago
Determine if the given mapping phi is a homomorphism on the given groups. If so, identify its kernel and whether or not the mapp
shtirl [24]

Answer:

(a) No. (b)Yes. (c)Yes. (d)Yes.

Step-by-step explanation:

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but the last statement is true if and only if G is abelian.

(b) Since G is abelian, it holds that

\phi(a)\phi(b)=a^nb^n=(ab)^{n}=\phi(ab)

which tells us that \phi is a homorphism. The kernel of \phi

is the set of elements g in G such that g^{n}=1. However,

\phi is not necessarily 1-1 or onto, if G=\mathbb{Z}_6 and

n=3, we have

kern(\phi)=\{0,2,4\} \quad \text{and} \quad\\\\Im(\phi)=\{0,3\}

(c) If z_1,z_2 \in \mathbb{C}^{\times} remeber that

|z_1 \cdot z_2|=|z_1|\cdot|z_2|, which tells us that \phi is a

homomorphism. In this case

kern(\phi)=\{\quad z\in\mathbb{C} \quad | \quad |z|=1 \}, if we write a

complex number as z=x+iy, then |z|=x^2+y^2, which tells

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\phi is not surjective.

(d) Remember that e^{ix}=\cos(x)+i\sin(x), using this, it holds that

\phi(x+y)=e^{i(x+y)}=e^{ix}e^{iy}=\phi(x)\phi(x)

which tells us that \phi is a homomorphism. By computing we see

that  kern(\phi)=\{2 \pi n| \quad n \in \mathbb{Z} \} and

Im(\phi) is the unit circle, hence \phi is neither injective nor

surjective.

7 0
3 years ago
Square root of 28<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B28%7D%20" id="TexFormula1" title=" \sqrt{28} " alt=" \sqrt{2
lidiya [134]
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4 0
4 years ago
Explain the full answer
Vilka [71]
Rememer you can do anything to an equaiton as long as you do it to both sides

and the erased answer is correct


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