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2 years ago

Explain how equal groups, multiplication, addition, and arrays related?

Mathematics

2 answers:

natulia [17]2 years ago

4 0

Answer:

An arrangement of objects, pictures, or numbers in columns and rows is called an array. Arrays are useful representations of multiplication concepts. This array has 4 rows and 3 columns. It can also be described as a 4 by 3 array.

Step-by-step explanation:

hope this helps i looked it up if not im srry

Alex Ar [27]2 years ago

4 0

Answer:

They are similar in many ways.

Step-by-step explanation:

Arrays are useful representations of multiplication concepts. Multiplication is similar to arrays because arrays use columns and rows to represent the digits and numbers in the equation. Addition is similar to the two because you can repeat it and you will get the same product (or sum). Equal groups are similar because it has the same number of items inside. It can be similar to all the others. So that is why they are related.

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What is the value of (f-g)(7)? f(x)=2+x;g(x)=x^2+5 (f-g)(7)=[1]

Sav [38]

Answer:

Alright so on this type of problem you just perform the operation they ask for, which in this case is subtraction.

Your first step will be to set up the problem:

f(x) - g(x)

Next you will substitute in your values:

(2x + 1) - (x2 - 7)

The easiest way to do the subtraction problems is to distribute your negative into your second set of parenthesis, so your expression would become:

2x + 1 - x2 + 7

Then combine your like terms:

2x - x2 + 8

Lastly put your expression in standard form (highest exponent to lowest)

-x2 + 2x + 8

Hope this helped!

Step-by-step explanation:

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Answer:

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2 years ago

Identify the quadratic function(s). (Select all that apply.)

Katen [24]

General Idea:

The quadratic function of the form $ax^2+bx+c=0$ .

Applying the concept:

Simplifying the equation in option A, we get...

$A) \; 8 - 5x = 4(3x - 1) \\Distributing \; 4 \; in \; right \; side \; of \; the \; equation. \\ \\ 8 - 5x = 12x - 4\\ The \; equation \; is \; a \; linear \; equation \; with \; variable \; on \; both \; sides.$

Simplifying the equation in option B, we get...

$B) \; \; (4a + 2)(2a - 1) + 1 = 0\\ Multiplying \; First \; \; Outer \; \; Inner \; \; Last \; terms\; in\; the \; left \; side.\\ \\ 4a \cdot 2a + 4a \cdot -1 + 2 \cdot 2a + 2 \cdot -1 + 1 = 0\\ \\ 8a^2-4a+4a-2+1=0\\ Combining \; like \; terms \; \\ \\ 8a^2 - 1 = 0\\ Above \; is \; a \; Quadratic \; Equation!$

Simplifying the equation in Option C, we get...

$C)\; \; 2y + 2(3y - 5) = 0\\ Distributing \; 2 \; in \; left \; side\\ \\ 2y+6y-10=0\\ Combining \; like \; terms\\ \\ 8y - 10 = 0\\ Above \; Equation \; is \; linear \; equation$

Simplifying the equation in Option D, we get

$D) \;2b(b - 7) + b = 0\\ Distributing \; 2b\; in \;the \;left\; side \;of \;the\;equation\\ \\ 2b \cdot b - 2b \cdot 7+b=0\\ Simplify \; in \; the \; left \; side \; of \; the \; equation\\ \\ 2b^2-14b+b=0\\ Combine \; like \; terms\\ \\ 2b^2-13b=0\\ Above \; equation \;is \;a \; Quadratic\;Equation!$