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3 years ago

Evaluate f(x) = 5x - 1 given the inputs (-1, 0,1,2)

Mathematics

1 answer:

Mice21 [21]3 years ago

5 0

Answer:

-6, -1, 4, 9

Step-by-step explanation:

You can substitute the values and do the arithmetic:

f(-1) = 5(-1) -1 = -5 -1 = -6

Or, you can recognize that the output values will increase by 5 for each increase of 1 in the input value.

f(0) = -6 +5 = -1

f(1) = -1 +5 = 4

f(2) = 4 +5 = 9

The (input, output) pairs are ...

(-1, -6), (0, -1), (1, 4), (2, 9)

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Number 12 please, need answers quick

fomenos

Answer:

Vectors are not the same as lengths.

Step-by-step explanation:

1. The error is that Vector AB + Vector BC = Vector AC

2. The same thing relates to the second analyses(Vector AD is equal Vector DC)

3. The third is all right.

8 0

4 years ago

Find the average value fave of the function f on the given interval. f(t) = e^sin(t) cos(t), [0, π/2]

RideAnS [48]

The question is related to integration and we have to used the following formula

$\frac{1}{b-a}\int\limits^a_b {f(x)} \, dx$

$\frac{1}{\pi /2 -0}\int\limits^0_{\pi/2} {e^{sin t}cos t } \, dt$

$= \frac{2}{\pi}(e^{sin t})_{0}^{ \pi /2}$

$=\frac{2}{\pi}(e^{sin(\pi/2)} -e^{sin0})$

$=\frac{2}{\pi}(e -1)$

6 0

3 years ago

Can someone help me please

Furkat [3]

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4 0

3 years ago

The value of x in the equation 4^(2x+5)=8^(3x)

Roman55 [17]

4⁽²ˣ ⁺ ⁵⁾ = 8³ˣ

But 4 = 2² and 8 = 2³

4⁽²ˣ ⁺ ⁵⁾ = 8³ˣ

2²⁽²ˣ ⁺ ⁵⁾ = (2³)³ˣ

Multiply out the powers, also since the

2⁴ˣ ⁺ ¹⁰ = 2⁹ˣ

Since the bases are the same, hence the powers are also the same.

4x + 10 = 9x

4x - 9x = -10

-5x = -10

x = -10/-5

x = 2

Hope this explains it.

3 0

3 years ago

A) Graph the following two lines on the same rectangular coordinate system. Show all your working. You need to use the slope-int

Oksanka [162]

Graph a.

3x+2y=12
-3x -3x

2y=-3x+12
2/2y=(3x+12)/2

y=-1.5x+6

graph b.

4x-y=5
+y +y

4x=y+5
-5 -5

4x-5=y

c) 11 units is the difference between y-coordinates of graph a and y-coordinates of graph b.

e) at (6,-3) x=6 cuts into graph a

8 0

4 years ago