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3 years ago

Is this true or false the terms 4xy and 5r have no common factors?

Mathematics

1 answer:

sveticcg [70]3 years ago

8 0

Answer: False, the only factor is 1 (please look at explaination)

Step-by-step explanation: 4 and 5 only have one factor in common which is 1.

Factors of 4 are:

1, 2, 4

The factors of 5 are:

1, 5

The only common factor is 1. 1 is the common factor of all the numbers. Then we have variables xy, r. they do not have anything in common so I am sure that the answer is false.

<u><em>Five stars please if the answer was correct.</em></u>

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A scuba diver swimming at the Deppe shown, and then swim 0.5 feet toward the surface every three seconds. What is the location o

ivanzaharov [21]

For every 3 seconds, the scuba diver dives 0.5 feet
after 15 seconds = your answer

3 x 5 = 15
0.5 x 5 = your answer

your answer = 2.5

2.5 is your answer

hope this helps

7 0

3 years ago

Which of the following is an equivalent equation obtained by completing the square of the expression below? x^2+6x−8=0 A (x+3)^2

valentina_108 [34]

Answer:

Solving the equation $x^2+6x-8=0$ by completing the square method we get $\mathbf{(x+3)^2=17}$

Option B is correct option.

Step-by-step explanation:

We need to solve the equation $x^2+6x-8=0$ by completing the square method.

For completing the square method: we need to follow: $a^2+2ab+b^2=(a+b)^2$

We are given:

$x^2+6x-8=0$

Solving by completing the square

$x^2+2(x)(?)+(?)^2-8=0$

We need to find ? in our case ? is 3 because 2*3= 6 and our middle term is 6x i,e 2(x)(3)=6x.

So, adding and subtracting (3)^2

$x^2+2(x)(3)+(3)^2-8-(3)^2=0\\(x+3)^2-8-9=0\\(x+3)^2-17=0\\(x+3)^2=17$

So, solving the equation $x^2+6x-8=0$ by completing the square method we get $\mathbf{(x+3)^2=17}$

Option B is correct option.

7 0

2 years ago

the cost of running an appliance varies jointly as the number of watts used, the hours of operation, and the cost per kilo-watt

zhuklara [117]

Suppose:
C=cost
c=cost per kilo-watt hour
w=number of watts
h=number of hours
thus
C=kwhc
where:
k=constant of proportionality:
k=C/(whc)
but
C=15 when w=6000, h=10/60=1/6 hours, c=7.5 cents per kw/h
thus
k=15/(6000*1/6*7.5)
k=0.002
thus:
C=0.002(whc)
hence:
when
h=70*2=140=140/6=70/3 hours the cost will be:
C=0.002(6000*70/3*7.5)
C=2100 cents
C=$21

7 0

3 years ago

lara [203]

Preston have to get some correct and some incorrect answers.

6 0

3 years ago

Read 2 more answers

Add the following:

PIT_PIT [208]

Step-by-step explanation:

1) 7/23 + 11/23 + 9/23

7+11+9/23

27/23

= 1 4/23

2) 2 5/7 + 9 4/7

11 9/7

= 11.12

3) 9/20 + 3/5

9+12/20

21/20

= 1 1/20 or 1.05

8 0

3 years ago