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4 years ago

In order for a solute to dissolve in a solvent, what must be true?

2 answers:

6 0

In order for a solute to dissolve in a solvent, the attractive forces in a solute need to be broken. So, the best option is A.

hodyreva [135]4 years ago

3 0

Answer: Option (A) is the correct answer.

Explanation:

When a solute is dissolved in a solvent then in order to dissolve the solute it is necessary that attractive forces between the solute must be broken such that solute molecules can combine with solvent molecules.

By increasing temperature, pressure, surface area etc of a solution we can break the attractive forces between the solute.

Thus, we can conclude that in order for a solute to dissolve in a solvent it is true that the attractive forces in a solute need to be broken.

You might be interested in

When two clear, colourless liquids are mixed together, a yellow precipitate is formed. This is an example of a

Flura [38]

Answer:

Combining the two clear colorless liquids is a chemical change.

Explanation:

Because a different solid substance is formed. Tell students that a precipitate is an insoluble solid that forms when two solutions are combined and react chemically. Insoluble means that the solid will not dissolve.

3 0

3 years ago

Consider the reaction of KOH with H3PO4 to form K3PO4 and H2O. If 5.38 g H3PO4 is reacted with excess KOH and 7.97 g of K3PO4 is

balu736 [363]

Answer:75%

Explanation:

First, the balanced reaction equation must be written out clearly as a guide to solving the problem. The molar masses of H3PO4 and K3PO4 are then calculated as they will be consistently required in solving the problem. The theoretical yield is obtained from the amount of H3PO4 reacted. Since 1 mole of H3PO4 yields 1 mole of K3PO4, 0.05 moles of H3PO4 yields 0.05 moles of K3PO4. The mass of K3PO4 is produced is then the product of 0.05 and it molar mass hence the theoretical yield. The % yield is calculated as shown.

7 0

3 years ago

2. If the reaction of 5.75 moles of sodium with excess hydrofluoric acid is able to produce 2.49 mol H2, what is the percent yie

GuDViN [60]

Answer:

86.5%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2Na + 2HF –> 2NaF + H2

Next, we shall determine the theoretical yield of the hydrogen gas, H2. This is illustrated:

From the balanced equation above,

2 moles of Na reacted to produce 1 mole of H2.

Therefore, 5.75 moles of Na will react to produce = (5.75 x 1)/2 = 2.88 moles of H2.

Therefore, the theoretical yield of Hydrogen gas, H2 is 2.88 moles.

Finally, we shall determine the percentage yield of Hydrogen gas, H2. This can be obtained as follow:

Actual yield of H2 = 2.49 moes

Theoretical yield of H2 = 2.88 moles

Percentage yield of H2 =.?

Percentage yield = Actual yield /Theoretical yield x 100

Percentage yield = 2.49/2.88 x 100

Percentage yield = 86.5%

Therefore, the percentage yield of Hydrogen gas, H2 is 86.5%.

6 0

3 years ago

What does the 2 in 2 CO represent?

Dmitry [639]

Carbon monoxide is the 2 in co

4 0

3 years ago

Read 2 more answers

Andreyy89

Answer:

The answer to your question is the second option

Explanation:

Reaction

Al₂(SO₄)₃ + KOH ⇒ Al(OH)₃ + K₂SO₄

Process

1.- Check if the reaction is already balanced

Reactants Elements Products

2 Aluminum 1

3 Sulfur 1

13 Oxygen 7

1 Potassium 2

1 Hydrogen 3

The reaction is unbalanced

2.- Balance the reaction

1Al₂(SO₄)₃ + 6KOH ⇒ 2Al(OH)₃ + 3K₂SO₄

Reactants Elements Products

2 Aluminum 2

3 Sulfur 3

18 Oxygen 18

6 Potassium 6

6 Hydrogen 6

Now the reaction is balanced. The coefficients are 1, 6, 2, 3.

5 0

3 years ago

Read 2 more answers