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kolbaska11 [484]
3 years ago
10

A growing concern in agricultural and food chemistry is the presence of residues in food. We use many forms of organic chemicals

in agriculture and food chemistry and there is growing concern as to how safe these materials are. Choose an organic chemical used in agricultural of food chemistry and report on the functional groups contained in your compound, the uses of the compound, and the safety of that compound. This research will require one or more outside sources. Ensure all citations are in APA format.
Chemistry
1 answer:
Anni [7]3 years ago
3 0

Answer:

Explanation:

Butylated Hydroxy Toluene, BHT, is one of the most famous synthetic additive in food chemistry. As an antioxidant, i t is used to increase the shelf life of food ( foods such as potato chips, breakfast cerals like chacos etc.).

The functional Functional in BHT are : two tertiary butyl groups, one methyl group and one -OH group on benzene ring

The uses of BHT include:

1. It is used primarily as antioxidant food additive.

2. In the production of cosmetics, rubbers, pharmaceuticals,BHT is also used as an antioxidant.

3. In petroleum industry, BHT is used in hydraulic fluids, turbine and gear oils etc

Someof the Safety of BHT include:

US Food and Drug administration recognised it as safe (GRAS) when used in permitted levels.

However, the present researches showed that excess use of BHT cause increased cancer risk, asthma and behavioural issues in children.

.

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A gas occupies a volume of 2.4 L at 14.1 kPa. What volume will the gas occupy at 84.6 kPa?
Naddik [55]

Answer:

  • <u>0.40 L</u>

Explanation:

Boyle's law for gases states that, at constant temperature, the volume and pressure of a fixed amount of gas are inversely related.

Mathematically, that is:

  • PV = constant

  • P₁V₁ = P₂V₂

Here, you have:

  • V₁ = 2.4 L
  • P₁ = 14.1 Kpa
  • P₂ = 84.6 KPa
  • V₂ = ?

Then, you can solve for V₂:

  • V₂ = P₁V₁ / P₂

Substitute and compute:

  • V₂ = 14.1 KPa × 2.4L / 84.6 KPa = 0.40 L ← answer
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Answer:

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Explanation:

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How many moles are in 3.86 x 1023 molecules of Carbon Dioxide (CO2)?
Yuri [45]

Answer:

<h2>0.64 moles </h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

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where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.86 \times {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{3.86}{6.02}  \\  = 0.641196...

We have the final answer as

<h3>0.64 moles</h3>

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