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saveliy_v [14]
3 years ago
11

cindy,jamal,and monique are dividing a piece of land using the lone divider method.after flipping coins monique has been selecte

d to be the divider and divides the land into three pieces.the values of the three pieces of land in the yes of the other players are shown below

Mathematics
1 answer:
lukranit [14]3 years ago
7 0

9514 1404 393

Answer:

The (piece, perceived values) are ...

  • Cindy, (3, 48%)
  • Jamal, (1, 39%)
  • Monique, (2, 33%)

Step-by-step explanation:

We assume the values and questions are as shown in the attachment.

1. After the division, Cindy bids only on piece 3, and Jamal bids only on piece 1. Hence the appropriate final division is ...

  Cindy: piece 3

  Jamal: piece 1

  Monique: piece 2

__

2. Monique divides the land so that the value of each piece to her is 33 1/3%. That is her perceived value for the piece she gets.

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I’m little confused can any explain? <br><br><br> (NO LINK PLS &lt;3)
Goshia [24]

Answer:

13

Step-by-step explanation:

To find the range substitute the value of x from the domain into the equation.

x = - 2 : y = -5(- 2) + 3 = 10 + 3 = 13

x = 0 : y = - 5(0) + 3 = 0 + 3 = 3

x = 1 : y = - 5(1) + 3 = - 5 + 3 = - 2

x = 3 : y = - 5(3) + 3 = - 15 + 3 = - 12

range is { - 12, - 2, 3, 13 }

with greatest value in the range being 13

6 0
2 years ago
Rewrite in simplest radical form square root of x times the fourth root of x. Show each step of your process.
Ipatiy [6.2K]

Answer:

\sqrt[4] {x^3}

Step-by-step explanation:

At this point, we can transform the square root into a fourth root by squaring the argument, and bring into the other root:

\sqrt x \cdot \sqrt[4] x =\sqrt [4] {x^2} \cdot \sqrt[4] x = \sqrt[4]{x^2\cdot x} = \sqrt[4] {x^3}

Alternatively, if you're allowed to use rational exponents, we can convert everything:

\sqrt x \cdot \sqrt[4] x = x^{\frac12} \cdot x^\frac14 = x^{\frac12 +\frac14}= x^{\frac24 +\frac14}= x^\frac34 = \sqrt[4] {x^3}

5 0
1 year ago
I NEED TO HAND IN NOW!!!
umka21 [38]

Step-by-step explanation:

a)

total no. of pupils is not more than 24

therefore first equation is

(x+y) ≤ 24. ....(1)

No. of girls exceeding the no. of boys by atleast 4

(y-x) ≥ 4. .....(2)

b) Now Liza chooses 8 boys

Maximum no. of girls = ?

Using first inequality

y+8= 24 ( maximum value of less than or equal to function is equal to itself)

Therefore,

y= 24-8

=16

Minimum no. of girls = ?

Using second inequality

y-8 =4 (minimum value of greater than or equal to function is equal to itself)

Therefore,

y= 4+8

y=12

Answer:

a) 2linear inequalities

(x+y) ≤ 24

(y-x) ≥ 4

b) Max no. of girls = 16

Min no. of girls = 12

Hope it helps...

5 0
3 years ago
Help due in 10 minutes
Fittoniya [83]

Answer:

II and III are right

Step-by-step explanation:

The reason I is wrong is the zeros are (-2, 0) and (4, 0)

8 0
3 years ago
I'm not sure ic I just leave like since I can't combine
sveticcg [70]
2\sqrt{12} - 7\sqrt{3} 
= 4\sqrt{3} - 7\sqrt{3}
= Since, we have same bases, we can subtract!
= To get,
= -3\sqrt{3} Answer
5 0
3 years ago
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