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2 years ago

A cone has volume 12 cubic inches. Its height is 4 inches. What is its radius?

Mathematics

2 answers:

irina [24]2 years ago

8 0

The radius of the cubic is 2.9

Gekata [30.6K]2 years ago

6 0

the radius of this cone is 2.9

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What is the equation, in slope-intercept form, of the line

OLga [1]

Answer:

y=1/3x_1/5=1/3×15=5_1/5×15=3. 5_3=2

7 0

3 years ago

..1+4=5. 2+5=12. 3+6=21. 8+11=40 or this could be 96 which is right and why

andre [41]

Multiply the numbers being added then add the first number. 4X1=4, 4+1=5.
2X5=10, 10+2=12. 11X8=88, 88+8=96. I'm not sure how to get 40, though.
Hope I could help.

7 0

3 years ago

What is the equation of the line in slope-intercept form?

Vaselesa [24]

I belive it would be y=-5/1x+6?

But im only like 90% sure so dont take my word for it but i hope that right?

4 0

3 years ago

Read 2 more answers

Write an equation that you can use to find the m

Ostrovityanka [42]

M =180 - 148-24 I THINK this shoud work

5 0

3 years ago

H(x)=

UNO [17]

The average rate of change of the function over −2 ≤ x ≤ 2 is 1/2

<h3>How to determine the average rate of change?</h3>

The function is given as:

$h(x) = \frac 18x^3 - x^2$

The interval is given as:

−2 ≤ x ≤ 2

Calculate h(2) and h(-2)

$h(2) = \frac 18 * 2^3 - (2)^2$

h(2) = -3

$h(-2) = \frac 18 * (-2)^3 - (-2)^2$

h(-2) = -5

The average rate of change is then calculated as:

$m = \frac{h(-2) - h(2)}{-2-2}$

This gives

$m = \frac{-5 + 3}{-4}$

Evaluate

m = 1/2

Hence, the average rate of change of the function over −2 ≤ x ≤ 2 is 1/2

Read more about average rate of change at

brainly.com/question/23715190

#SPJ1

<u>Complete question</u>

$h(x) = \frac 18x^3 - x^2$

What is the average rate of change of h over the interval −2 ≤ x ≤ 2

7 0

1 year ago