How many moles of KOH are in 130.0 mL of a 0.85 M solution of KOH?

t 745 K, the reaction below has an equilibrium constant (Kc) of 5.00 × 102. H2 (g) + I2 (g) ⇌ 2 HI (g) If a mixture of 0.10 mol

spayn [35]

Answer : The concentration of HI (g) at equilibrium is, 0.643 M

Explanation :

The given chemical reaction is:

$H_2(g)+I_2(g)\rightarrow 2HI(g)$

Initial conc. 0.10 0.10 0.50

At eqm. (0.10-x) (0.10-x) (0.50+2x)

As we are given:

$K_c=5.00\times 10^2$

The expression for equilibrium constant is:

$K_c=\frac{[HI]^2}{[H_2][I_2]}$

Now put all the given values in this expression, we get:

$5.00\times 10^2=\frac{(0.50+2x)^2}{(0.10-x)\times (0.10-x)}$

x = 0.0713 and x = 0.134

We are neglecting value of x = 0.134 because the equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.0713

The concentration of HI (g) at equilibrium = (0.50+2x) = [0.50+2(0.0713)] = 0.643 M

Thus, the concentration of HI (g) at equilibrium is, 0.643 M

8 0

4 years ago

Using the appropriate Ksp values, find the concentration of K+ ions in the solution at equilibrium after 600 mL of 0.45 M aqueou

Alekssandra [29.7K]

Answer:

[K⁺] = 0.107 M

[OH⁻] = 1.13 × 10⁻⁹ M

Explanation:

600 mL of 0.45 M Cu(NO3)2 gives equal mole of Cu²⁺ and (NO₃)²⁻

⇒ 0.45 × 600 × 10⁻³

= 0.27 moles of Cu²⁺ and (NO₃)²⁻

450 mL of 0.25 M KOH gives equal moles of K⁺ and OH⁻

⇒ 0.25 × 450 × 10⁻³

= 0.1125 moles of K⁺ and OH⁻

Now after mixing 0.1125 moles of OH⁻ precipitates 0.05625 moles of Cu²⁺ (because 1 Cu²⁺ needs 2 OH⁻)

Therefore , moles of remaining Cu²⁺ = 0.27 - 0.05625

=0.21375 moles which is equal to :

⇒ 0.21375/(( 600+450))× 10⁻³

= 0.21375/1050 × 10⁻³

= 0.20357 M

Given that :

(Ksp for Cu(OH)2 is 2.6 × 10⁻¹⁹)

We know that , Ksp = [Cu²⁺][OH⁻]²

2.6 × 10⁻¹⁹ = 0.20357 × [OH⁻]²

[OH⁻]² = 2.6 × 10⁻¹⁹/0.20357

[OH⁻] = 1.13 × 10⁻⁹ M

[K⁺] = moles of K⁺ /total volume

[K⁺] = 0.1125 / 1050 × 10⁻³

[K⁺] = 0.107 M

6 0

3 years ago

HBr + H2SO4 = SO2 + Br2 + H2O Did S change oxidation number?

galben [10]

Answer: I think the answer might be yes..

Explanation:

7 0

3 years ago

Read 2 more answers

Which words have the most negative connotation a)pain b)agony c)discomfort d)distress

gladu [14]

the the answer is b agony

8 0

3 years ago

Read 2 more answers

Hydrogen chloride gas and oxygen react to form water vapor and chlorine gas. What volume of water would be produced by this reac

AlladinOne [14]

Answer: 3.4 L

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given Volume}}{\text {Molar Volume}}=\frac{6.5L}{22.4L}=0.29moles$

The balanced chemical equation for reaction of Hydrogen chloride gas with oxygen to form water vapor and chlorine gas.

$4HCl(g)+O_2(g)\rightarrow 2H_2O(g)+2Cl_2(g)$

According to stoichiometry :

4 moles of $HCl$ produce = 2 moles of $H_2O$

Thus 0.29 moles of $HCl$ will produce = $\frac{2}{4}\times 0.29=0.15moles$ of $H_2O$

Volume of $H_2O=moles\times {\text {Molar Volume}}=0.15moles\times 22.4L/mol=3.4L$

Thus 3.4 L of of water would be produced by this reaction if 6.5 L of hydrogen chloride were consumed

4 0

3 years ago