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GarryVolchara [31]
2 years ago
5

What is the correct mathematical relationship between the number of moles, the volume, and the standard molar volume of a substa

nce?
Chemistry
2 answers:
tekilochka [14]2 years ago
8 0

Answer:

V_{m} = \frac{V}{n}

Explanation:

Molar volume is the volume occupied by 1 mole of a substance.

For gases, based on the ideal gas law we have:

PV = nRT

where, P = pressure, V= volume, n = moles, R = gas constant, T = temperature

\frac{V}{n} = \frac{RT}{P}

Here, the molar volume is given as:

V_{m} = \frac{V}{n}

Under standard temperature and pressure conditions, the molar volume of an ideal gas is 22.4 L/mol

vitfil [10]2 years ago
4 0
The relationship is:
standard molar volume = volume / moles
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Part complete When a 235 92U nucleus is bombarded by neutrons (10n) it undergoes a fission reaction, resulting in the formation
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<u>Answer:</u> The isotopic symbol of barium is _{56}^{138}\textrm{Ba} and that of strontium is _{38}^{89}\textrm{Sr}

<u>Explanation:</u>

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In a nuclear reaction, the total mass and total atomic number remains the same.

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^{235}_{92}\textrm{U}+^1_0\textrm{n}\rightarrow ^A_Z\textrm{Ba}+^{94}_{36}\textrm{Kr}+3^1_0\textrm{n}

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Total mass on reactant side = total mass on product side

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Total atomic number on reactant side = total atomic number on product side

92 + 0 = Z + 36 + 0

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The isotopic symbol of barium is _{56}^{139}\textrm{Ba}

  • For the given fission reaction:

^{235}_{92}\textrm{U}+^1_0\textrm{n}\rightarrow ^A_Z\textrm{Sr}+^{143}_{54}\textrm{Xe}+3^1_0\textrm{n}

  • <u>To calculate A:</u>

Total mass on reactant side = total mass on product side

235 + 1 = A + 143 + 3

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  • <u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

92 + 0 = Z + 54 + 0

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The isotopic symbol of strontium is _{38}^{89}\textrm{Sr}

Hence, the isotopic symbol of barium is _{56}^{138}\textrm{Ba} and that of strontium is _{38}^{89}\textrm{Sr}

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What term describes a carbon atom that has four different groups bonded to it?
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Polarized Light and Chiral Carbon:
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