Question

Hydrogen chloride gas and oxygen react to form water vapor and chlorine gas. What volume of water would be produced by this reaction if 6.5 L of hydrogen chloride were consumed? Also, be sure your answer has a unit symbol, and is rounded to the correct number of significant digits.

Answer 1

Answer: 3.4 L

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given Volume}}{\text {Molar Volume}}=\frac{6.5L}{22.4L}=0.29moles$

The balanced chemical equation for reaction of Hydrogen chloride gas with oxygen to form water vapor and chlorine gas.

$4HCl(g)+O_2(g)\rightarrow 2H_2O(g)+2Cl_2(g)$

According to stoichiometry :

4 moles of $HCl$ produce = 2 moles of $H_2O$

Thus 0.29 moles of $HCl$ will produce =$\frac{2}{4}\times 0.29=0.15moles$  of $H_2O$

Volume of $H_2O=moles\times {\text {Molar Volume}}=0.15moles\times 22.4L/mol=3.4L$

Thus 3.4 L of of water would be produced by this reaction if 6.5 L of hydrogen chloride were consumed