Answer:
13r²(2rs + 4r³ - 3s⁴)
Step-by-step explanation:
In equation 26r³s + 52r⁵ - 39r²s⁴;
The GCF of 26, 52, and 39 = 13
The GCF of r³, r⁵ and r² = r²
The GCF of s, (no "s"), and s⁴ = no "s" (Since one of the number doesn't have "s")
Now we can factor out 13r² from all three expressions;
26r³s + 52r⁵ - 39r²s⁴
=> <em>13r²(2rs) + 13r²(4r³) - 13r²(3s⁴)</em>
To factor it all together;
<u>13r²(2rs + 4r³ - 3s⁴)</u>
Hope this helps!
Step-by-step explanation:
The way to find missing numbers in equivalent ratios is to multiply the means (the first denominator and the second numerator) and multiply the extremes (the first numerator and the second denominator). It sounds really complicated, but it is quite simple =)
2/5 = x/10
The means in this equivalent ration are 5 and x. The extremes are 2 and 10.
5x = 20
Now solve =)
x = 4
That was pretty simple. Let's move on to the next one. Do exactly the same thing here:
4/10 = 6/x
60 = 4x
15 = x
That was pretty simple, too! Keep going!
6/15 = x/25
15x = 150
x = 10
All of these should be equal, so check them by dividing:
2/5 = 0.4
4/10 = 0.4
6/15 = 0.4
10/25 = 0.4
They all check out, so these are your answers: 2/5, 4/10, 6/15, 10/25
I really hope this helps you =)
X=3 or 3.5, I know that it isn't a direct answer but you asked this question yesterday and have gotten nothing so I will help narrow it down for you.
Answer:
difference in volume = 26.96h cm³
Step-by-step explanation:
The volume of a prism is the product of the base area and the height. A trapezoid prism has a trapezium as the base shape. Therefore,
volume of a trapezoid prism = area of a trapezium × height
area of the base(trapezoid) = 140 cm²
Volume = 140h
Volume of a cylinder = πr²h
where
r = radius
h = height
volume = πr²h
volume = π × 6² × h
volume = 3.14 × 36 × h
volume = 113.04h
To know how much larger the volume of the prism is than the volume of the cylinder we have to take the difference of the volume.
Recall the height are the same
difference in volume = 140h - 113.04h
difference in volume = 26.96h cm³
Answer:
6.5
Step-by-step explanation:
DeltaMath