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Tomtit [17]
3 years ago
9

Company B: starting salary-28,000 Yearly salary increase-2,400

Mathematics
1 answer:
Naya [18.7K]3 years ago
5 0

Answer:

Sharla, 4400

Step-by-step explanation:

Paul's Salary:

Paul started at company B. Starting salary of company B is $ 28,000 with a yearly increase of $ 2,400. Paul's Salary in first year will be 28,000. In second year his salary will be 28000 + 2400, in 3rd year his salary will be: 28000 + 2(2400) and so on.

Since, the increase in Paul's salary every year is $ 2400, the increase in his salary after 10 years or in 10th year would be = 2400 x 9 = $ 21,600

So, his total salary in 10th year would be = 28000 + 21600 = $ 49,600

Sharla's Salary:

Sharla started at company C. Starting salary of company C is $ 36,000 with a yearly increase of $ 2,000.

Since, the increase in Sharla's salary every year is $ 2000, the increase in her salary after 10 years or in 10th year would be = 2000 x 9 = $ 18,000

So, her total salary in 10th year would be = 36000 + 18000 = $ 54,000

Conclusion:

Sharla earned more in 10th year an amount equal to $ 4400. So the answer is:

In the last year, <u>Sharla</u> earned <u>$4,400</u> more.

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