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cupoosta [38]
2 years ago
9

Complete the table of values for the equation, 16x + 4y = 12.

Mathematics
1 answer:
Ann [662]2 years ago
7 0

The x-y coordinates for the given equation are: (-2,11),(-1,7),(0,3), (1,-1) and (2,-5).

<h3>Linear Function</h3>

A linear function can be represented by a line. The standard form for this equation is: ax+b , for example, y=2x+7. Where:

  • a= the slope;
  • b=the constant term that represents the y-intercept.

The given equation is 16x + 4y = 12. For solving this question, you should replace the given values of x  for finding the values of y.

Thus,

  • For x= -2,  the value of y will be:

       16*(-2)+4y=12

      -32+4y=12

      4y=12+32

     4y=44

      y=11

  • For x= -1,  the value of y will be:

         16*(-1)+4y=12

  • -16+4y=12
  • 4y=12+16
  • 4y=28
  • y=7
  • For x= 0,  the value of y will be:

         16*(0)+4y=12

  • 0+4y=12
  • 4y=12
  • 4y=12
  • y=3
  • For x= 1,  the value of y will be:

         16*(1)+4y=12

  • 16+4y=12
  • 4y=12-16
  • 4y=-4
  • y= -1
  • For x= 2,  the value of y will be:

         16*(2)+4y=12

  • 32+4y=12
  • 4y=12-32
  • 4y=-20
  • y= -5

Read more about the linear equation here:

brainly.com/question/1884491

#SPJ1

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Step-by-step explanation:

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A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 0.499, \sigma = 0.002

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So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.504 - 0.494}{0.002}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.496 - 0.494}{0.002}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

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