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adoni [48]
3 years ago
14

The product of two consecutive odd integers is 99. If

Mathematics
1 answer:
bonufazy [111]3 years ago
5 0

The equation in terms of x is x(x + 2) = 99 or x^2 + 2x - 99 = 0

The pairs of integers are  -11 and -9 or 9 and 11

<em><u>Solution:</u></em>

Let the two consecutive odd integers be x and x + 2

Let "x" be the smallest integer

Given that product of two consecutive odd integers is 99

To find: an equation in terms of  x

Product of x and x + 2 = 99

x(x + 2) = 99\\\\x^2 + 2x = 99\\\\x^2 + 2x - 99 = 0

Thus the equation in terms of x is found

Let us solve the above equation to find all pairs of integers

Solve the quadratic equation by grouping method

Middle term 2x can be written as 11x - 9x

\rightarrow x^2 + 2x - 99 = 0\\\\\rightarrow x^2 + 11x - 9x -99 = 0

Now group the terms,

\rightarrow (x^2 + 11x) - (9x + 99) = 0

Take "x" as common term from first group and 9 as common term from second group

\rightarrow x(x + 11)-9(x+ 11) = 0

Now take x + 11 as common term,

\rightarrow (x + 11)(x - 9) = 0

Equating to zero we get,

x + 11 = 0 or x - 9 = 0

x = -11 or x = 9

<em><u>When x = -11 :</u></em>

x + 2 = -11 + 2 = -9

Thus first set of two consecutive odd integers are -11 and -9

<em><u>When x = 9 :</u></em>

x + 2 = 9 + 2 = 11

Thus second set of two consecutive odd integers are 9 and 11

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