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Alisiya [41]
3 years ago
6

If you cut a 35-inch long stick in the ratio 2:3, how long would each part be?

Mathematics
1 answer:
boyakko [2]3 years ago
6 0
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Wendy thinks the perfect chocolate chip cookie has 353535 chocolate chips for every 555 ounces of dough. Cookie Club makes batch
poizon [28]

Answer:

The Cookie Club cookies have less chocolate chips then Wendy does.

Step-by-step explanation:

35/5= 7 100/15= 6 1/3

7 0
2 years ago
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The corner where the states of Utah, New Mexico, and Colorado meet is called the Four Corners.
kogti [31]
If Utah is angle a and Colorado is angle b and Arizona is angle c and New Mexico is angle d Angle a and d are vertical angles angle b and c are vertical angles 
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3 years ago
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The scatterplot shows the time it takes for a new hot plate to boil various amounts of water, and one lab group’s attempt at a l
Vera_Pavlovna [14]

so it will

be

E=>6^5 H2O 9^+7*8

7 0
3 years ago
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Prove that (4n+1)^2(4n-1)^2 is a multiple of 8 for all integers of n.<br><br> thanks.
azamat

Answer: i think  (4n+1)^2(4n-1)^2 isnt a multiple of 8 for all integers of n because:

(4n + 1)²(4n - 1)²

= [(4n + 1)(4n - 1)]²

= (16n² - 1)²

= 16².n².n² - 2.16.n² + 1

= 8n²(32n² - 4) + 1

can see 8n²(32n² - 4) is a multiple of 8 but 1 isnt a multiple of 8

=> (4n + 1)²(4n - 1)² isnt a multiple of 8 for all integers of n.

Step-by-step explanation:

6 0
3 years ago
A chemist wants to make 100 liters of a 44% acid solution. She has solutions that are 20% acid and 60% acid.
alexgriva [62]

the first solution is 20% acid, and say we'll be using "x" liters, so how many liters of just acid are in it?  well 20% of "x" or namely 0.2x.  Likewise for the 60% acid solution, if we had "y" liters of it, the amount of only acid in it is 0.6y.

\begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{liters of }}{amount}\\ \cline{2-4}&\\ \textit{1st solution}&x&0.20&0.2x\\ \textit{2nd solution}&y&0.60&0.6y\\ \cline{2-4}&\\ mixture&100&0.44&44 \end{array}~\hfill \begin{cases} x+y=100\\\\ 0.2x+0.6y=44 \end{cases}

x+y=100\implies y=100-x~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.2x+0.6(100-x)=44} \\\\\\ 0.2x+60-0.6x=44\implies -0.4x+60=44\implies -0.4x=-16 \\\\\\ x=\cfrac{-16}{-0.4}\implies \boxed{x=40}~\hfill \boxed{\stackrel{100-40}{y=60}}

7 0
2 years ago
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