If I am rolling a single dice what is the probability of rolling a number that is divisible by 2 and 3? The only number divisible by 2 and 3 is 6. So, would the answer be 1 out 6 or 1/6
Answer:
Option B. -j = -h/-k is not correct
Step-by-step explanation:
As from the given scenario both the negative signs will be cancelled out giving positive j : -h/-k = -j
First option has: -j = -h/k In this case also the negative sign from both sides would be cancelled out.
Second option has: -h/-k = -j In this case negative signs cannot be cancelled out.
Third option has: h/-k = -j , negative sign would be cancelled from both sides.
Fourth option has: h/k = j , no negative sign on either side.
i hope it will help you!
Answer:
4= 29 
+6
all I know is number fourr T-T I tried yw
Step-by-step explanation:
You will use the ratio 4:8 to create a part to part to whole ratio.
First simplify 4:8 to 1:2, then make it 1:2:3 (Salt:Sugar:Total).
Use this to find the volume of sugar. 2 sugars for every 3 total would be equivalent to 200 cubic feet of sugar for every 300 total cubic feet.
Since the dice are fair and the rolling are independent, each single outcome has probability 1/15. Every time we choose
We have 
and 
, because the dice are fair.
Now we use the assumption of independence to claim that
Now, we simply have to count in how many ways we can obtain every possible outcome for the sum. Consider the attached table: we can see that we can obtain:
- 2 in a unique way (1+1)
- 3 in two possible ways (1+2, 2+1)
- 4 in three possible ways
- 5 in three possible ways
- 6 in three possible ways
- 7 in two possible ways
- 8 in a unique way
This implies that the probabilities of the outcomes of 
are the number of possible ways divided by 15: we can obtain 2 and 8 with probability 1/15, 3 and 7 with probability 2/15, and 4, 5 and 6 with probabilities 3/15=1/5
