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3 years ago

Convert into mixed number 81/3 and -29/2

2 answers:

8 0

Hmmmm to convert from improper to mixed, simply do the division of both, the quotient gets upfront, the remainder as the numerator, for example,

how many times 3 goes into 81? well, 27 times, with a remainder of 0, thus $\bf 27\frac{0}{3}$

how many times does 2 go into 29? well 14 times, with a remainder of 1, thus $\bf -14\frac{1}{2}$

babymother [125]3 years ago

7 0

81/3 is 27

-29/2 is -14.5

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An equation with more than one variable is called a "literal Equation"

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Eduardo spent half of his weekly allowance on clothes. To earn more money his parents let him weed the garden for $8. What is hi

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Answer: his weekly allowance is $8

The model to solve the problem is

X/2+8=12

Step-by-step explanation:

To get Eduardo's weekly allowance

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x/2+8=12

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Answer:

$x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12$

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

$\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}$

Second equation:

$\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}$

Third equation:

$\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}$

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

$1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}$

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

$\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}$

Now we use this value for "x" back in equation 1 to solve for "y":

$1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}$

And finally we solve for the third unknown "z":

$\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12$

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3 years ago

In the figure below, ∠DEC ≅ ∠DCE, ∠B ≅ ∠F, and segment DF is congruent to segment BD . Point C is the point of intersection betw

Rzqust [24]

Answer:

Step-by-step explanation:

Given:

∠DCE ≅ ∠DEC

∠B ≅ ∠F

DF ≅ BD

To prove:

ΔABC ≅ ΔGFE

Solution:

Statements Reasons

1). ∠DCE ≅ ∠DEC 1). Given

2). ∠ACB ≅ ∠GEF 2). Vertically opposite angles to the

congruent angles.

3). ∠B ≅ ∠F 3). Given

4). DB ≅ DF 4). Given

5). DC + CB ≅ DE + EF 5). Segment addition postulate

6). DC ≅ DE 6). Property of isosceles triangle

7). CB ≅ EF 7). Transitive property

8). ΔABC ≅ ΔGFE 8). ASA property of congruence

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3 years ago

The larger of two consecutive integers is 7 greater than twice the smaller. Find the integers.

belka [17]

Answer:

8,9

Step-by-step explanation:

(x +1) + 7=2x

x+8 = 2x

8=x

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3 years ago