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melamori03 [73]
4 years ago
7

‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️PLEASE HELP!!! PLEASE EXPLAIN AND ONLY ANSWER IF YOU KNOW YOU HAVE THE CORRECT ANSWE

R!!!
Evaluate the following expression using the values given:

x^3 - 2y^2 - 3x^3 + z^4

X=3 y=5 z = -3
Mathematics
1 answer:
Lena [83]4 years ago
7 0

We are given the expression x³ - 2y² - 3x³ + z⁴. We have to evaluate it at a given set of x, y, and z values. Before then, let's combine like terms.

x³ - 2y² - 3x³ + z⁴

= -2x³ - 2y² + z⁴ <-- by combining like terms

Now we evaluate for x=3 y=5 z = -3

= -2(3³) - 2(5²) + (-3⁴) <-- by putting in for x, y, z

= -2(27) - 2(25) + 81 <--- parentheses and exponents first in order of operations

= -54 - 50 + 81 <---- multiplication is next

= -4 + 81

= 77


Thus, we evaluate and it's 77.

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nadezda [96]
<h3>RESPUESTA</h3><h3>la recta numérica también puede medirse en centímetros</h3>
7 0
4 years ago
Pls answer this i want to know ok ok ok ok ok
bogdanovich [222]

Step-by-step explanation:

given \\ (x +  \frac{1}{x} ) = 7 \\ now \\ (x +  \frac{1}{x} ) ^{2}   \\ (7) ^{2} (given) \\ 49 \\ again \\  {x}^{2}  + ( \frac{1}{x} ) ^{2}  \\ (x  +   \frac{1}{x}) ^{2}  - 2 \times x \times  \frac{1}{x}  \\ (7) ^{2}  - 2 \\ 49 - 2 \\ 47

6 0
3 years ago
Evaluate f(t)=-2t^2+ 1 for f(-3). please help
VARVARA [1.3K]

Answer:

-17

Step-by-step explanation:

f(t)=-2t^2+ 1

f(-3)=-2*-3^2+1

f(-3)=-2*9+1

f(-3)=-18+1

f(-3)=-17

5 0
4 years ago
Pls pls help it is due todayyy
Pani-rosa [81]

Answer:

I did this today and its H

Step-by-step explanation:

Please lmk if im wrong, but im sure its right but js ;)

6 0
3 years ago
PLEASE HEEEELPPPP ASAP
denpristay [2]

Answer:

y = √(3² + 3²)

9 = √(5² + x²)

Step-by-step explanation:

Diagram 1:

Hypotenuse = y

Opposite = 3

Adjacent = 3

y² = 3² + 3²

y = √(3² + 3²)

y = √(9 + 9)

y = √18

Diagram 2:

Hypotenuse ² = known leg² + unknown leg²

Hypotenuse = 9

Known leg = 5

Unknown leg = x

9² = 5² + x²

9 = √(5² + x²)

9² = 5² + x²

9² - 5² = x²

x² = 81 - 25

x = √ 56

5 0
3 years ago
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