The difference of the square of a number and 28 is equal to 3 times that number

1. Graph the function f(x)=4cos(x). (Be sure to label your x-axis.)

Mekhanik [1.2K]

ANSWER

To graph the function

$y=4cos(x)$ we need to plot some few points within one period. Since the interval is not given, we shall use $[0,2 \pi]$ '

$\left \begin{array}{cc}x&y=4cos(x)\\0 &4\\\frac{\pi}{2}&0 \\ \pi&-4\\\frac{3\pi}{2} &0\\2\pi&4\end{array}\right$ .

We plot the above points to obtain the graph as shown in the attachment.

6 0

3 years ago

Can somebody help me. Will Mark brainliest.

cricket20 [7]

Answer:

around 81.2 degrees

Step-by-step explanation:

use inverse tangent

remeber tan = O/H

divide it first

84/13

6.461538461538462

then use invese tan( $tanx^{-1}$ )

81.20258929000894

or around 81.2 degrees

4 0

3 years ago

2 sin^2 (x) -5 sin (x) -3=0

andreyandreev [35.5K]

we have that

$2sin^{2} x-5sin x-3=0$

I. Rewrite the equation by substituting the expression u in for sin x.

$2u^{2} -5u-3=0$

II. Factor the quadratic expression. Rewrite the equation with factors instead of the original polynomial.

$2u^{2} -5u-3=0$ is equal to

using a graph calculator-----> see the attached figure

$(u-3)*(2u+1)=0$

III. Use the zero product property to solve the quadratic equation.

$(u-3)*(2u+1)=0$

(u-3)=0--------------> u=3

(2u+1)=0-------- 2u=-1------> u=-1/2-----> u=-0.5

IV. Rewrite your solutions to Part III by replacing u with sin x.

sin x=3--------> is not the solution (sin x can not be greater than 1)

sin x=-0.50------>is the solution

V. Solve the remaining equations for x, giving all solutions to the equation.

sin x=-0.50

if the sine is negative

then

x belong to the III or IV quadrant

we know that

sin 30°=0.50

so

the solution for the III quadrant is

x=180°+30°-------> x=210°

the solution for the IV quadrant is

x=360°-30°------> x=330°

5 0

3 years ago

What is the largest domain?

Elenna [48]

The largest domain for this is answer C [-1,1]

7 0

3 years ago

Let (-7, 2) be a point on the terminal side of 0.

nekit [7.7K]

By applying the definitions of trigonometric functions, the exact values of the sine, secant and tangent of the point on the terminal side are $\sin \theta = \frac{2}{\sqrt{53}}$ , $\sec \theta = -\frac{\sqrt{53}}{7}$ and $\tan \theta = -\frac{2}{7}$ .

<h3>How to determine the exact values</h3>

In this question we need to find the exact values of three trigonometric functions associated with the terminal side of an angle. The following definitions are used:

Sine

$\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}$ (1)

Secant

$\sec \theta = \frac{\sqrt{x^{2}+y^{2}}}{x}$ (2)

Tangent

$\tan \theta = \frac{y}{x}$ (3)

If we know that x = - 7 and y = 2, then the exact values of the three trigonometric functions:

Sine

$\sin \theta = \frac{2}{\sqrt{53}}$

Secant

$\sec \theta = -\frac{\sqrt{53}}{7}$

Tangent

$\tan \theta = -\frac{2}{7}$

By applying the definitions of trigonometric functions, the exact values of the sine, secant and tangent of the point on the terminal side are $\sin \theta = \frac{2}{\sqrt{53}}$ , $\sec \theta = -\frac{\sqrt{53}}{7}$ and $\tan \theta = -\frac{2}{7}$ .

<h3>Remark</h3>

The statement reports typing errors, correct form is shown below:

Let (x, y) = (- 7, 2) be a point on the terminal side of θ. Find the exact value of sin θ, sec θ and tan θ.

To learn more on trigonometric functions: brainly.com/question/6904750

#SPJ1

5 0

1 year ago