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stich3 [128]
2 years ago
6

Find the area of the figure.

Mathematics
1 answer:
seraphim [82]2 years ago
7 0

\huge \bf༆ Answer ༄

At first Divide the figure into two rectangles, I and Il

Area of figure l is ~

  • \sf24 \times (40 - 30)

  • \sf24 \times 10

  • \sf240 \:  \: ft {}^{2}

Area of figure ll is ~

  • \sf 18 \times 30

  • \sf540 \: ft{}^{2}

Area of whole figure = Area ( l + ll )

that is equal to ~

  • \sf240 + 540

  • \sf780 \:  \: ft{}^{2}

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The box plot show the weights in ounces of 15 different bags of almonds. About how many bags contained less than 27 ounces:
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Answer:

See explanation

Step-by-step explanation:

The question is incomplete, as the box plot is not given. A general approach to the question, is as follows:

First, identify the 27 mark on the box plot.

Next, count the number of data less than 27.

Take, for instance, there are 6  dots or marks before 27;

This means that 6 bags contain  less than 27 ounces

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What type of number is 0? Rational, Irrational, Whole number, Integer
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The junior varsity football team score 23 points in last Saturday's game they score the combination of seven point touchdowns in
frutty [35]

Answer:

  2 touchdowns, 3 field goals

Step-by-step explanation:

The number of touchdowns cannot be more than 3, so it is relatively easy to find the solution by trial and error.

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7 0
3 years ago
I NEED HELP ASAP!!
castortr0y [4]

9514 1404 393

Answer:

  • 3 big bucks
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Step-by-step explanation:

Let B, L, D represent the numbers of big bucks, little bucks, and does, respectively.

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  D = 5 + 2L . . . . . . . . . 5 more does than twice the number of little bucks

  B = L/2 . . . . . . . . . . . . half as many big bucks as little bucks

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We can substitute for B and D in the first equation:

  L/2 + L + (5 +2L) = 26

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  L = 6 . . . . . . . . . . . . . . . . . multiply by 2/7

  D = 5 + 2·6 = 17

  B = 6/2 = 3

The party bagged 3 big bucks, 6 little bucks and 17 does.

3 0
3 years ago
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