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2 years ago

Find the area of the figure.

Mathematics

1 answer:

seraphim [82]2 years ago

7 0

$\huge \bf༆ Answer ༄$

At first Divide the figure into two rectangles, I and Il

Area of figure l is ~

$\sf24 \times (40 - 30)$

$\sf24 \times 10$

$\sf240 \: \: ft {}^{2}$

Area of figure ll is ~

$\sf 18 \times 30$

$\sf540 \: ft{}^{2}$

Area of whole figure = Area ( l + ll )

that is equal to ~

$\sf240 + 540$

$\sf780 \: \: ft{}^{2}$

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3 years ago

Anna has a 25-meter-long fence that she plans to use to enclose a rectangular garden of width w. The fencing will be placed arou

Leviafan [203]

<h3>Answer: -2w^2 + 25w = 25 or -2w^2 + 25w - 25 = 0</h3>

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Explanation:

Refer to the diagram below. The width is w. We have two opposite and parallel sides equal to this. The other two parallel congruent sides are L = 25-2w meters long. We start with the total amount of fencing, and then subtract off the two width values, so 25-w-w = 25-2w.

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Area = L*W

Area = (25-2w)*w

Area = 25w - 2w^2

Area = -2w^2 + 25w

Set this equal to the desired area (25 square meters) to get

-2w^2 + 25w = 25

and we can subtract 25 from both sides to get everything on one side

-2w^2 + 25w - 25 = 0

side note: The two approximate solutions of this equation are w = 1.0961 and w = 11.4039 (use the quadratic formula or a graphing calculator to find this)