<span>se
sen x = 3/5 eleva ao quadrado ambos os lados
sen² x = (3/5)²
Tem que partir da relação fundamental
sen²x + cos²x = 1
(3/5)² + cos² x = 1
cos² x = 1 - (3/5)² = 16/25
cos x = V(16/25 = 4/5
b ) tg x = sen x / cos x = 3/5 / 4/5 = 3/5 * 5/4 = 3/4
c) cotg x = cosx / sen x = 1 / tgx = 1/ (3/4 = 4/3
d) sec x = 1/ cos x = 1 / 4/5 = 5/4
e) cossec x = 1 / sen x = 1/ 3/5 = 5/3
se gostou , avalie
edson</span>edson <span>· 9 anos atrás</span>
Answer:
The answer is the fourth option, a+2b
Step-by-step explanation:
Answer: (-1,-6) because you are just changing the y-axis when reflecting over the x-axis so the x-value doesn't change.
A linear function does indeed form a line.