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4 years ago

Which of the following is true?

Mathematics

2 answers:

Lelechka [254]4 years ago

8 0

I think b is true hope it help

deff fn [24]4 years ago

4 0

The answer is the third one.

A triangle can have more than one acute angle. Look at equilateral triangles. The three angles are acute, 60.

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Given the following sets.

svet-max [94.6K]

It looks like the ∩ sign may be missing from the question. If you mean to find A∩C, called the intersection, you're looking for elements that are both in A and C.

{0, 2} qualifies.

6 0

4 years ago

Read 2 more answers

Please help me! I'm spending 50 points on this question and my last two questions never even got answered!

Verdich [7]

Answer:

Step-by-step explanation:

Domain is only affected if certain values can make the result something that either doesn't make sense or is an error. In your situation, it wants you to find the domain of f/g, which is a fraction. The only rule we have for fractions regarding domain is that we simply can't divide by zero, to find the domain for any fraction with variables in the denominator, what I do is take the denominator, set it equal to 0, and solve for x.

So, if we're taking f/g, we have:

$\frac{3x^2 + x^4 + 2}{4x - 3}$

4x - 3 makes up our denominator, the bottom part of the fraction. So

4x - 3 = 0

4x = 3

x = 3/4

So the denominator is equal to zero when x is equal to 3/4. This would produce an error in any calculator because you can't divide by zero. The domain here is all real numbers except for 3/4.

(For future problems, the only thing to look out for is if your numerator, the top part of the fraction, factors into something that cancels with the bottom. In that case, it wouldn't affect domain because you aren't actually dividing by anything. For example:

$\frac{x^2 - 4}{x-2}$

If we factor the top, we see that x^2 - 4 = (x - 2)(x + 2). In this case, we have (x - 2) in both the top and bottom of the fraction, so it cancels out, and from there nothing else is restricting our domain. It would be all real numbers in a case like that.)

8 0

3 years ago

Which graph represents <br> y= -2x?

Kamila [148]

It would be the second graph since the coefficient is negative

5 0

3 years ago

Read 2 more answers

Help me solve this pleaseee

Drupady [299]

Since they are equal to 90 degrees. (complimentary angles)

6x-11+7x+10= 90

Combine like terms.

13x-1= 90

Add one to both sides.

13x= 91

x= 7

Plug that into the b.

7(7)+10

49+10

59

I hope this helps!
~kaikers

3 0

4 years ago

The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control a

Dafna11 [192]

Answer:

Probability that at least 490 do not result in birth defects = 0.1076

Step-by-step explanation:

Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.

To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects

Proof -

Given that,

P(birth that result in a birth defect) = 1/33

P(birth that not result in a birth defect) = 1 - 1/33 = 32/33

Now,

Given that, n = 500

X = Number of birth that does not result in birth defects

Now,

P(X ≥ 490) = $\sum\limits^{500}_{x=490} {^{500} C_{x} } (\frac{32}{33} )^{x} (\frac{1}{33} )^{500-x}$

= ${^{500} C_{490} } (\frac{32}{33} )^{490} (\frac{1}{33} )^{500-490}$ + .......+ ${^{500} C_{500} } (\frac{32}{33} )^{500} (\frac{1}{33} )^{500-500}$

= 0.04541 + ......+0.0000002079

= 0.1076

⇒Probability that at least 490 do not result in birth defects = 0.1076

4 0

3 years ago