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3 years ago

I need help graphing the points of C = 100S + 2800.

Mathematics

2 answers:

avanturin [10]3 years ago

5 0

Answer:

y = mx + b

C = 100s + 2800

100 is the slope

2800 is the y-int

Graph Below:

yarga [219]3 years ago

4 0

Answer:

Step-by-step explanation:

C = 100S + 2800

so ur y intercept is : (0,2800)

ur x intercept can be found by subbing in 0 for y (or in this case C) and solving for x (or in this case S)

0 = 100S + 2800

-100S = 2800

S = -2800/100

S = -28

so ur x intercept is (-28,0)

so plot ur intercept points (0,2800) and (-28,0)

and u have a slope of 100....or 100/1

so start at (-28,0).....move up 100 and to the right 1....plot that.....move up 100 and to the right 1.....plot that.....keep following this pattern....ur line will eventually cross the y axis at (0,2800)

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Solve the problem. Find the amount of money in an account after 12 years if $4700 is deposited at 5% annual interest compounded

Dmitrij [34]

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The correct answer is $8532.17

Step-by-step explanation:

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3 0

3 years ago

I answered it but I just need someone to answer just to make sure mine are right

Artemon [7]

<h2>The missing measures of the angles are:</h2>

$m\angle 1= 60^{\circ}\\\\m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

<u>Given</u>:

$m\angle Z = 138^{\circ}$

<em><u>Note the following:</u></em>

An equilateral triangle has all its three angles equal to each other. Each angle = $60^{\circ}$ .

This implies that, since $\triangle WXY$ is equilateral, therefore, $m\angle Y = m\angle XWY = m\angle XYW = 60^{\circ}$

Base angles of an isosceles triangle are congruent to each other.

This implies that, since $\triangle WZY$ is isosceles, therefore, $m\angle 3 = \angle 5$

Applying the above stated, let's find the measure of each angle:

Find $m\angle 1$

$m\angle 1 = 60^{\circ}$ (an angle in an equilateral triangle equals 60 degrees)

Find $m\angle 2$

$m\angle 2 = 60 - m \angle 3$

$m\angle 2 = 60 -\frac{1}{2}(180 - 138)$ $(Note: \frac{1}{2}(180 - 138) = 1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 2 = 60 -21\\\\m\angle 2 = 39^{\circ}$

Find $m\angle 3$ and $m\angle 5$ (base angles of isosceles triangle WZY)

$m\angle 3 = \frac{1}{2}(180 - 138) (1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 3 = \frac{1}{2}(42) \\\\m\angle3 = 21^{\circ}$

$m\angle3 = m\angle 5$ (base angles of isosceles triangle are congruent)

Therefore,

$m\angle5 = 21^{\circ}$

Find $m\angle 4$

$m\angle 4 = 60 - m\angle 5$

Substitute

$m\angle 4 = 60 - 21\\\\m\angle 4 = 39^{\circ}$

The missing measures of the angles are:

$m\angle 1= 60^{\circ}\\\\ m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

Learn more here:

brainly.com/question/2944195

5 0

2 years ago

Help?? Ty!! for the help much love!!

Leviafan [203]

Your answer is C. :)

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3 years ago