Let x represent amount invested in the higher-yielding account.
We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be
.
We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.
, where,
I = Amount of interest,
P = Principal amount,
r = Annual interest rate in decimal form,
t = Time in years.
We are told that interest rates are 6% and 10%.


Amount of interest earned from lower-yielding account:
.
Amount of interest earned from higher-yielding account:
.

Let us solve for x.



Therefore, the man invested $30,000 at 10%.
Amount invested in the lower-yielding account would be
.
Therefore, the man invested $60,000 at 6%.
Step-by-step explanation:
thats is all,just subject of formula
Answer:
5/2
Step-by-step explanation:
duh
Answer:
15 I think
Step-by-step explanation:
Answer
The first 10 terms of thjs sequence are 2, 5, 8, 11, 14, 17, 20, 23, 26, 29
Explanation:
You can notice that to get to the next term, you have to add 3.
So we add 3 every next term