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Alex Ar [27]
4 years ago
7

What is BXF another one??

Mathematics
1 answer:
8090 [49]4 years ago
3 0
Answer: 58

Explanation:
AXF = 90 (this is a right angle, which is 90 degrees)
AXG = 32 (this is given)

Subtract AXF - AXG:
= 90 - 32
= 58
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23 is what percent of 184?​
Brilliant_brown [7]

if we take 184 as the 100%, what is 23 off of it in percentage?

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2 years ago
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Graph y= 1/2x–3 . Please. Just please.
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I don't have a graph, but I can try to show you how to do it.

Go to -3 on the y-axis (the vertical one in the middle)

Put a dot there. That's your y-intercept.

From the dot go up 1 line, then go right 2 lines.

Put a dot where you end up. Continue doing so until you get enough for your graph.

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rue or false: It is common to denote random variables by upper-case letters and particular values of the random variables by the
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true

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2 years ago
Lori creates the following design for a T-shirt.
kakasveta [241]

<u>Solution-</u>

From the figure,

AE = 2.4

EB = 2.8

BC = 11.7


Area of rectangle 1 = 8.68 sq.in

\Rightarrow FH \times HI=8.68

\Rightarrow EB \times HI=8.68  (∵ sides of the rectangle 2)

\Rightarrow 2.8 \times HI=8.68

\Rightarrow HI=3.1


Area of Triangle 1 = 6.48 sq.in

\Rightarrow \frac{1}{2}\times AE \times EG= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+FG)= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+HI)= 6.48  (∵ sides of the rectangle 1)

\Rightarrow EF+3.1= 5.4

\Rightarrow EF=2.3

\Rightarrow BH=2.3  (∵ sides of the rectangle 2)


BC = BH+HI+IC

\Rightarrow 11.7= 2.3+3.1+IC

\Rightarrow IC=6.3


The area of Rectangle 2,

=EB\times BH =2.8\times 2.3=6.44\ sq.in


The area of Triangle 2,

\frac{1}{2}\times GI \times IC=\frac{1}{2}\times EB \times IC=\frac{1}{2}\times 2.8 \times 6.3=8.82\ sq.in


The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2

= 6.48+8.68+8.82+6.44=30.42 sq.in


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3 years ago
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maksim [4K]

Answer:

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A line parallel to y = 2x has exactly the same slope but a different y-intercept, b.

Start with y = mx + b, and replace m with 2, y with -1 and x with -2:

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