2 to the power of 20/3 to the power of 8. 2^20/3^8 for short.
Given - Taisha has a general goal is to burn the 280 calories.
she is varies by the 25 calories.
Find out the maximum and minimum of calories burn by the taisha.
To proof -
let us assume that the calories burn by the taisha be x.
as given the calories are varies by the 25 calories.
then the maximum calories equation becomes
x-25 = 280
x = 280 + 25
x = 305
the maximum calories burn by the taisha is 305 calories.
minimum calories equationbecomes
x + 25 = 280
x = 255
The minmum calories burn by the taisha is 255 calories.
Hence proved
Answer:
1.
a = 112
b = 68
c = 68
2.
a = 127
3.
a=35
b=40
c=35
d=70
4.
a= 30
b=70
c = 30
d=70
e = 130
I'll help you with the rest later
Step-by-step explanation:
a = 112 because of allied angles rule
b and c = 68 because of angles at a point
360-112-112 ÷2
2. a = 127 because of angles on a straight line rule.
180-38-15
3. d= 70, vertically opposite angle
using angles on a straight line, 180 - 70 - 40 ÷ 2
we now have the two angles and because they are vertically opposite a and c = 35
b = 40 because of vertically opposite angles
4. a=30 because 90-70
since a=30, take 90 - 30 to get b, 70
d= 70, vertically opposite angles
e = 130 because a+b+c, vertically opposite angles
Answer:
Step-by-step explanation:
4u + 8v = -3u + 2v
Solving 4u + 8v = -3u + 2v
Solving for variable 'u'.
Move all terms containing u to the left, all other terms to the right.
Add '3u' to each side of the equation. 4u + 3u + 8v = -3u + 3u + 2v
Combine like terms: 4u + 3u = 7u 7u + 8v = -3u + 3u + 2v
Combine like terms: -3u + 3u = 0 7u + 8v = 0 + 2v 7u + 8v = 2v
Add '-8v' to each side of the equation. 7u + 8v + -8v = 2v + -8v
Combine like terms: 8v + -8v = 0 7u + 0 = 2v + -8v 7u = 2v + -8v
Combine like terms: 2v + -8v = -6v 7u = -6v
Divide each side by '7'. u = -0.8571428571v
Simplifying u = -0.8571428571v
