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aleksklad [387]
3 years ago
13

Convert 25/8 into a mixed number

Mathematics
1 answer:
motikmotik3 years ago
3 0
Changing improper fractions to mixed form or mixed numbers is a very simple thing. You just have to follow the following:
Then write Let us have 25/8. <span><span>
1.       </span><span>Divide the numerator (top number)  by the denominator (number below the bar). </span></span> Simply divide 25 by 8. 25 ÷ 8 = n
We can have 3 and 1 as a remainder. So, the answer will be 3 and 1/8. <span><span>

2.       </span> <span>Write down the whole number answer. 
Since we have 3 as the whole number answer, write it down. And;</span></span> <span><span>

3.       </span><span> Write down any remainder above the denominator, like this:</span></span> 3 and 1 (remainder) over 8 (denominator of the given improper fraction). That is, 3 1/8  


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Natali [406]
You need to remember that 100 pence = 1 pound sterling.
Halve both sides:                    50 pence = 1/2 pound sterling
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                                50 pence          50 pence
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Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin
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Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let \mu = <em><u>mean duration of 15-sided union rugby games after the meeting.</u></em>

So, Null Hypothesis, H_0 : \mu \geq 185 minutes      {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, H_A : \mu < 185 minutes     {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean duration of 15-sided union rugby games = 179 min

            s = sample standard deviation = 12 minutes

            n = sample of 15-sided rugby games = 36

So, <u><em>the test statistics</em></u>  =  \frac{179-185}{\frac{12}{\sqrt{36} } }  ~ t_3_5

                                       =  -3

The value of t test statistics is -3.

<u>Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

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Step-by-step explanation:

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