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aleksklad [387]
3 years ago
13

Convert 25/8 into a mixed number

Mathematics
1 answer:
motikmotik3 years ago
3 0
Changing improper fractions to mixed form or mixed numbers is a very simple thing. You just have to follow the following:
Then write Let us have 25/8. <span><span>
1.       </span><span>Divide the numerator (top number)  by the denominator (number below the bar). </span></span> Simply divide 25 by 8. 25 ÷ 8 = n
We can have 3 and 1 as a remainder. So, the answer will be 3 and 1/8. <span><span>

2.       </span> <span>Write down the whole number answer. 
Since we have 3 as the whole number answer, write it down. And;</span></span> <span><span>

3.       </span><span> Write down any remainder above the denominator, like this:</span></span> 3 and 1 (remainder) over 8 (denominator of the given improper fraction). That is, 3 1/8  


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A ball dropped from the top of a building can be modeled by the function f(t)=-16^2+36, where t represents time in seconds
Viefleur [7K]

Answer:

The ball is dropped from a height of 36 feet

The bee and the ball will collide after approximately 1.3 seconds

The bee and the ball will collide at approximately 8 feet above the ground

The ball hits the ground after 1.5 seconds

Step-by-step explanation:

<u><em>The complete question is</em></u>

A ball dropped from the top of the building can be modeled by the function f(t)=-16t^2 + 36 , where t represents time in seconds after the ball was dropped. A bee's flight can be modeled by the function, g(t)=3t+4, where t represents time in seconds after the bee starts the flight.

The graph represents the situation.

select all that apply

1) The bee launches into flight from the ground.

2) The ball is dropped from a height of 36 feet.

3) The bee and the ball will collide after approximately 1.3 seconds.

4) The bee and the ball will collide after approximately 8 seconds.

5) The bee and the ball will collide at approximately 8 feet above the ground.

6) The bee and the ball will not collide.

7) The ball hits the ground after 1.5 seconds

see the attached figure to better understand the problem

<u><em>Verify all the options</em></u>

case 1) The bee launches into flight from the ground.

The statement is false

Because

we have

g(t)=3t+4

For t=0

g(t)=3(0)+4=4\ ft

That means ----> The bee launches into flight from a height 4 feet above the ground

case 2) The ball is dropped from a height of 36 feet

The statement is true

Because

For t=0

f(t)=-16(0)^2+36=36\ ft

case 3) The bee and the ball will collide after approximately 1.3 seconds

The statement is true

Because

Equate f(t) and g(t)

-16t^2+36=3t+4

-16t^2-3t+32=0

solve the quadratic equation by graphing

The solution is t=1.324 sec

see the attached figure N 2

case 4) The bee and the ball will collide after approximately 8 seconds

The statement is false

Because, the bee and the ball will collide after approximately 1.3 seconds (see case 3)

case 5) The bee and the ball will collide at approximately 8 feet above the ground

The statement is true

Because

For t=1.324 sec

substitute the value of t in f(t) or g(t)

g(t)=3(1.324)+4=7.97\ ft

case 6) The bee and the ball will not collide

The statement is false

see case 3) and case 5)

case 7) The ball hits the ground after 1.5 seconds

The statement is true

Because

we know that

The ball hit the ground when the value of f(t) is equal to zero

so

For f(t)=0

-16t^2+36=0

t^2=\frac{36}{16}

t=\frac{6}{4}=1.5\ sec

4 0
3 years ago
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3 years ago
What’s the answer too this problem I can’t solve?
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I'm using PEDMAS.

Multiplication first.

2 • 4 = 8

Subtraction.

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Please let me know if you spot any errors (especially the fraction operation)
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8(2x-3)-6x if 3=x and simplify
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Simplify the expression:

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for x=3

put value of "x" to the expression:

<u>10×3 - 24 = 30 - 24 = 6</u>
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A coin is flipped until 3 heads in succession occur. list only those elements of the sample space that require 6 or less tosses.
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we are given

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so, firstly, we will find sample space

S={HHH , THHH , HTHHH, TTHHH , TTTHHH , HTTHHH , THTHHH , HHTHHHH, ......}

now, we are given that

list only those elements of the sample space that require 6 or less tosses

so, we can see that sample space

S={HHH , THHH , HTHHH, TTHHH , TTTHHH , HTTHHH , THTHHH , HHTHHHH, ......}

There are infinite such possibilities

so, there are infinite number of elements in space

and we know that

discrete sample space will always have finite elements

but we have infinite number of sample space elements here

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6 0
3 years ago
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