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Paladinen [302]

3 years ago

13

please help! i will give brainiest Ann's car can go miles on gallons of gas. During a drive last weekend, used of gas. How far

did drive? Use pencil and paper. Explain how the problem changes if you were given the distance drove last weekend instead of how much gas used.

1 answer:

iragen [17]3 years ago

3 0

Answer:

I LOVE YOU MORE

Step-by-step explanation:

You might be interested in

-7x+4= 18<br> set notation<br> interval notation

denpristay [2]

Answer:

Step-by-step explanation:

-7x+4=18

-7x=14

Divide-7 on both sides of the equal sign which is going to leave you with x=-2

7 0

2 years ago

Consider a family with 4 children. Assume the probability that one child is a boy is 0.5 and the probability that one child is a

jarptica [38.1K]

Answer:

a) Total 16 possibilities

MMMM

FFFF

MMMF

MMFM

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FFMF

FMFF

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b) P(MMMM) = 1/16

5 0

3 years ago

How do I graph -4x+6y=12

eimsori [14]

You have 2 options.

I will show you the most efficient one, but later I will tell you the other.

-4x+6y=12

6y=4x+12

y=4/6x+12

y=2/3x+12

This tells us the point (0,12) as 12 is where it meets the y-axis (that is why you add it)

And then using the slope, 2/3 we can get (2,15) (which is up 3, right 2)

Just graph those, I would show you exactly, but I cannot add attachments sadly.

The other way (which I won’t show it all as the results would end out with the same line) is to fill in x, then y, with 0

So -4*0+6y=12 which means x=0 and you are solving for y and -4x+6*0=12 which means y=0 and you are solving for x

8 0

3 years ago

evaluate the fermi function for an energy KT above the fermi energy. find the temperature at which there is a 1% probability tha

dybincka [34]

Complete Question

Evaluate the Fermi function for an energy kT above the Fermi energy. Find the temperature at which there is a 1% probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron.

Answer:

a

The Fermi function for the energy KT is $F(E_o) = 0.2689$

b

The temperature is $T_k = 1261 \ K$

Step-by-step explanation:

From the question we are told that

The energy considered is $E = 0.5 eV$

Generally the Fermi function is mathematically represented as

$F(E_o) = \frac{1}{e^{\frac{[E_o - E_F]}{KT} } + 1 }$

Here K is the Boltzmann constant with value $k = 1.380649 *10^{-23} J/K$

$E_F$ is the Fermi energy

$E_o$ is the initial energy level which is mathematically represented as

$E_o = E_F + KT$

So

$F(E_o) = \frac{1}{e^{\frac{[[E_F + KT] - E_F]}{KT} } + 1}$

=> $F(E_o) = \frac{1}{e^{\frac{KT}{KT} } + 1}$

=> $F(E_o) = \frac{1}{e^{ 1 } + 1}$

=> $F(E_o) = 0.2689$

Generally the probability that a state, with an energy 0.5 eV above the Fermi energy, will be occupied by an electron is mathematically represented by the Fermi function as

$F(E_k) = \frac{1}{e^{\frac{[E_k - E_F]}{KT_k} } + 1 } = 0.01$

Here $E_k$ is that energy level that is 0.5 ev above the Fermi energy $E_k = 0.5 eV + E_F$

=> $F(E_k) = \frac{1}{e^{\frac{[[0.50 eV + E_F] - E_F]}{KT_k} } + 1 } = 0.01$

=> $\frac{1}{e^{\frac{0.50 eV ]}{KT_k} } + 1 } = 0.01$

=> $1 = 0.01 * e^{\frac{0.50 eV ]}{KT_k} } + 0.01$

=> $0.99 = 0.01 * e^{\frac{0.50 eV ]}{KT_k} }$

=> $e^{\frac{0.50 eV ]}{KT_k} } = 99$

Taking natural log of both sides

=> $\frac{0.50 eV }{KT_k} } =4.5951$

=> $0.50 eV =4.5951 * K * T_k$

Note eV is electron volt and the equivalence in Joule is $eV = 1.60 *10^{-19} \ J$

So

$0.50 * 1.60 *10^{-19 } =4.5951 * 1.380649 *10^{-23} * T_k$

=> $T_k = 1261 \ K$

7 0

2 years ago

Joe work for 7 hours and earned 105.00 write the rate what is unit rate

Eduardwww [97]

Answer:

15 Dollars per hour

Step-by-step explanation:

Because 15 * 7 = 105

7 0

2 years ago