First we need to write the null and alternate hypothesis for this case.
Let x be the average number of text message sent. Then
Null hypothesis: x = 100
Alternate hypothesis: x > 100
The p value is 0.0853
If p value > significance level, then the null hypothesis is not rejected. If p value < significance level, then the null hypothesis is rejected.
If significance level is 10%(0.10), the p value will be less than 0.10 and we reject the null hypothesis and CAN conclude that:
The mean number of text messages sent yesterday was greater than 100.
If significance level is 5%(0.05), the p value will be greater than 0.05 and we cannot reject the null hypothesis and CANNOT conclude that:
The mean number of text messages sent yesterday was greater than 100.
Answer:
2255÷86=26
4309÷43=100
7944÷15=529.6
Step-by-step explanation:
I dont have step by step srry
Is this shape 3d and no offense your 28 you should know this stuff. like im 15 and I know more than u MOHAHA
The greatest common factor is 6xa
If you multiply 6xa with a and x ----> 6xa(x+a), you'll get <span>6x^2a + 6xa^2</span>
Answer:
D
Step-by-step explanation:
It is opposite of one the angles on the same line as n so it is the same value