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kramer
3 years ago
10

Ruby had 30 dollars to spend on 3 gifts. She spent 9 7 10 dollars on gift A and 5 2 5 dollars on gift B. How much money did she

have left for gift C?
Mathematics
1 answer:
atroni [7]3 years ago
7 0

Answer:

$14 9/10

Step-by-step explanation:

Ruby had 30 dollars to spend on 3 gifts. She spent 9 7 10 dollars on gift A and 5 2 5 dollars on gift B. How much money did she have left for gift C?

From the above question,

$30 = Gift A + Gift B + Gift C

She spent 9 7/ 10 dollars on gift A and 5 2/5 dollars on gift B.

$30 = $9 7/10 + $5 2/5 + Gift C

Gift C = $30 - ( $9 7/10 + $5 2/5)

Lowest Common Denominator = 10

Gift C = $30 - $14+(7 + 4/10)

Gift C = $30 - $14+(7 + 4/10)

Gift C = $30 - $14+(11/10)

$30 - $14+(1 1/10)

$30 - $15 1/10

Gift C = $14 9/10

Therefore, the amount of money she had left for gift C is $14 9/10

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