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saw5 [17]
3 years ago
14

What is this answer tell me plz?

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
8 0
X-6=-11

Do the inverse to the other side. So, add 6.

x-6(+6)= -11(+6)

x= -5

I hope this helps!
~kaikers
cricket20 [7]3 years ago
5 0
-11+6= -5
the answers is -5
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Plz help guys! I will mark everyone who answers correctly for each one! Plz!
ryzh [129]

Answer:

Let's say that x is sam's age and y is Amy's age

x=y-4

and five years ago:

x-5=(y-5)/2

y-4-5=(y-5)/2

2y-18=y-5

y=13

x=9

then:

sam's age is 9 and Amy's age is 13

5 0
2 years ago
Read 2 more answers
M(x)=x(x+6)<br> p(x)=x(x+3)²-9<br><br> Show that m(x) and p(x) are equivalent
mamaluj [8]

Answer:

m=x+6

Step-by-step explanation:

Let's solve for m.

mx=x(x+6)

Step 1: Divide both sides by x.

2x/x=    x²+6x/x

m=x+6

Hope this helps :)

PLS BRAINLIEST

5 0
2 years ago
The number of gallons of water in a large tank at time (t) minutes is given by the function W(t)=160,000-8,000t+t². Find the ave
sergij07 [2.7K]

The number of gallons of water in the tank at t=10 is

... W(10) = 160,000 -10(8000 -10) = 80100

The number of gallons of water in the tank at t=10.5 is

... W(10.5) = 160,000 -10.5(8000 -10.5) = 76110.25

The rate of change over the interval is

... (W(10.5) - W(10))/(10.5 - 10) = (76110.25 - 80100)/(0.5) = -7979.5

The average rate of change in the number of gallons of water in the tank over the interval is -7979.5 gal/min.

The sign is negative, so the amount of water is decreasing.

3 0
3 years ago
Help me pleaseeee xo
dolphi86 [110]

Answer:

12

Step-by-step explanation:

4 0
3 years ago
Max makes and sells posters. The function p(x)= -10x^2 +200x -250, graphed below, indicates how much profit he makes in a month
viktelen [127]
Here is our profit as a function of # of posters
p(x) =-10x² + 200x - 250
Here is our price per poster, as a function of the # of posters:
pr(x) = 20 - x
Since we want to find the optimum price and # of posters, let's plug our price function into our profit function, to find the optimum x, and then use that to find the optimum price:
p(x) = -10 (20-x)² + 200 (20 - x) - 250
p(x) = -10 (400 -40x + x²) + 4000 - 200x - 250
Take a look at our profit function. It is a normal trinomial square, with a negative sign on the squared term. This means the curve is a downward facing parabola, so our profit maximum will be the top of the curve.
By taking the derivative, we can find where p'(x) = 0 (where the slope of p(x) equals 0), to see where the top of profit function is.
p(x) = -4000 +400x -10x² + 4000 -200x -250
p'(x) = 400 - 20x -200
0 = 200 - 20x
20x = 200
x = 10                         
p'(x) = 0 at x=10. This is the peak of our profit function. To find the price per poster, plug x=10 into our price function:
price = 20 - x
price = 10
Now plug x=10 into our original profit function in order to find our maximum profit:
<span>p(x)= -10x^2 +200x -250
p(x) = -10 (10)</span>² +200 (10) - 250
<span>p(x) = -1000 + 2000 - 250
p(x) = 750

Correct answer is C)
</span>
7 0
3 years ago
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