Two years ago, Sally had 5,000 dogs in her dog shelter. Now she has 24,575 dogs. The rate of change is 391.5 % increase
<em><u>Solution:</u></em>
Given that Two years ago, Sally had 5,000 dogs in her dog shelter
Now she has 24,575 dogs
To find: rate of change
A rate of change is a rate that describes how one quantity changes in relation to another quantity
<h3><u>Steps to follow:</u></h3>
- First: work out the difference (increase) between the two numbers you are comparing.
- Increase = New Number - Original Number.
- Then: divide the increase by the original number and multiply the answer by 100.
- % change = Increase ÷ Original Number x 100
![\text {rate of change }=\frac{\text { new value }-\text {original value}}{\text {original value}} \times 100](https://tex.z-dn.net/?f=%5Ctext%20%7Brate%20of%20change%20%7D%3D%5Cfrac%7B%5Ctext%20%7B%20new%20value%20%7D-%5Ctext%20%7Boriginal%20value%7D%7D%7B%5Ctext%20%7Boriginal%20value%7D%7D%20%5Ctimes%20100)
![\begin{array}{l}{\text { rate of change }=\frac{24,575-5000}{5000} \times 100} \\\\ {\text { rate of change }=\frac{19575}{5000} \times 100=391.5}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Ctext%20%7B%20rate%20of%20change%20%7D%3D%5Cfrac%7B24%2C575-5000%7D%7B5000%7D%20%5Ctimes%20100%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7B%20rate%20of%20change%20%7D%3D%5Cfrac%7B19575%7D%7B5000%7D%20%5Ctimes%20100%3D391.5%7D%5Cend%7Barray%7D)
Thus the rate of change is 391.5 % increase
I think this was ur question Rachel bought 1,500 shares of Cawh Consolidated Bank at a price of $24.85 each. As the price climbed, she sold off parts of her holdings. She sold off 250 shares at $28.32 apiece, she sold 800 of her shares at $33.60 apiece, and she sold off the remainder of her shares at $39.94 apiece. If Rachel's broker charges a commission of $65 per $1,000 of stock bought or sold, how much profit did Rachel make, to the nearest dollar?
I think the answer is 8,859? I don't know what the question was, but I think that's it. Hope this helps. c;
Given:
f(x) is an exponential function.
![f(-0.5)=27](https://tex.z-dn.net/?f=f%28-0.5%29%3D27)
![f(1.5)=21](https://tex.z-dn.net/?f=f%281.5%29%3D21)
To find:
The value of f(0.5), to the nearest hundredth.
Solution:
The general exponential function is
![f(x)=ab^x](https://tex.z-dn.net/?f=f%28x%29%3Dab%5Ex)
For, x=-0.5,
![f(-0.5)=ab^{-0.5}](https://tex.z-dn.net/?f=f%28-0.5%29%3Dab%5E%7B-0.5%7D)
...(i)
For, x=1.5,
![f(1.5)=ab^{1.5}](https://tex.z-dn.net/?f=f%281.5%29%3Dab%5E%7B1.5%7D)
...(ii)
Divide (ii) by (i).
![\dfrac{21}{27}=\dfrac{ab^{1.5}}{ab^{-0.5}}](https://tex.z-dn.net/?f=%5Cdfrac%7B21%7D%7B27%7D%3D%5Cdfrac%7Bab%5E%7B1.5%7D%7D%7Bab%5E%7B-0.5%7D%7D)
![\dfrac{7}{9}=b^2](https://tex.z-dn.net/?f=%5Cdfrac%7B7%7D%7B9%7D%3Db%5E2)
Taking square root on both sides, we get
![\dfrac{\sqrt{7}}{3}=b](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%7B7%7D%7D%7B3%7D%3Db)
![b\approx 0.882](https://tex.z-dn.net/?f=b%5Capprox%200.882)
Putting b=0.882 in (i), we get
![27=a(0.882)^{-0.5}](https://tex.z-dn.net/?f=27%3Da%280.882%29%5E%7B-0.5%7D)
![27=a(1.0648)](https://tex.z-dn.net/?f=27%3Da%281.0648%29)
![\dfrac{27}{1.0648}=a](https://tex.z-dn.net/?f=%5Cdfrac%7B27%7D%7B1.0648%7D%3Da)
![a\approx 25.357](https://tex.z-dn.net/?f=a%5Capprox%2025.357)
Now, the required function is
![f(x)=25.357(0.882)^x](https://tex.z-dn.net/?f=f%28x%29%3D25.357%280.882%29%5Ex)
Putting x=0.5, we get
![f(0.5)=25.357(0.882)^{0.5}](https://tex.z-dn.net/?f=f%280.5%29%3D25.357%280.882%29%5E%7B0.5%7D)
![f(0.5)=23.81399](https://tex.z-dn.net/?f=f%280.5%29%3D23.81399)
![f(0.5)\approx 23.81](https://tex.z-dn.net/?f=f%280.5%29%5Capprox%2023.81)
Therefore, the value of f(0.5) is 23.81.