The volume of a cylinder depends on both the cylinder's height and its radius.
There are an infinite number of different cylinders, all with different dimensions,
that all have 300π inches³ of volume. In order to calculate either dimension of
a cylinder, both the volume and the other dimension must be known.
We sense a high probability that the picture described as "shown below"
tells the cylinder's radius. Sadly, we have not been made privy to that
bit of information, leaving us out in the cold with no way to calculate the
cylinder's height.
Lateral Area of a cylinder is ; 2πR.H
R=12 mm and H= 15 mm
Then LATERAL area = 2π(12)(15) =48π ≈ 150 mm²
Answer:
$121,052.63
Step-by-step explanation:
Tomando en cuenta la fórmula " (1+i)^(n) ". Sustituyes los valores quedando así
(1 + 0.055)^12 y te da como resultado 1.90
Por último divides $230,000 entre 1.90 y ahí tienes el resultado final.
You want to know when both colleges have the same enrollment. "When" is a time thing so you are going to be solving for x. The number of students is the same and that means you will be solving for y.
Since both ys are equal, you can equate the right side of each equation to each other.
0.046 x + 0.570 = - 0.036x + 2.702 There are a number of ways to go on. The easiest is to dig out your calculator. Add 0.036x to both sides.
0.046x + 0.036x + 0.570 = 2.702
0.082x + 0.570 = 2.702 Now subtract 0.570 from both sides.
0.082x = 2.702 - 0.570
0.082x = 2.132 Divide by 0.084
x = 2.132 / 0.082
x = 26 which means you add 26 onto 1990. The year this took place was 2016
x = 2016 (That's the year there was equality in enrollment). The second one is the only year that gives 2016 as an answer. So you don't have to find y. But we'll do it anyway.
Now you have to solve for y
y = 0.046x +0.57 put 26 in for x
y = 0.046 * 26 + 0.570
y = 1.196 + 0.570
y = 1.766 enrollment numbers were equal, but this is in thousands.
y = 1766 enrollment in actual numbers of students.
Second choice <<<<<===== answer.
Answer:
The answer is 286.
Step-by-step explanation:
<u>13! can be rewritten</u> as 13*12*11*10!.
Since <u>10! is on the top and bottom of the fraction</u>, we can<em> eliminate them</em>. We are then left with 13*12*11/3!.
3! = 6. We can <u>eliminate the 6 from the denominator by diving the 12 by 6</u> in the numerator to get 13*11*2.
Finally, we can can evaluate the expression to get 286.
